Given a + B + C = 0, ABC = 8, it is proved that 1 / A + 1 / B + 1 / C is less than 0

Given a + B + C = 0, ABC = 8, it is proved that 1 / A + 1 / B + 1 / C is less than 0

It is easy to know that there are two negative numbers and one positive number in a, B and C
Let a ≤ B < 0 < C
1/a=bc/8,1/b=ac/8,1/c=ab/8
1/a+1/b+1/c=(ab+bc+ac)/8
=[a(b+c)+bc]/8
=(-a²+bc)/8
Because - A & # 178; < 0, BC < 0
So - A & # 178; + BC < 0, that is (- A & # 178; + BC) / 8 < 0
So 1 / A + 1 / B + 1 / C < 0

Elden Ring Premiere

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