It is known that a, B and C satisfy a + B + C = 0 and ABC = 8. It is proved that 1 / A + 1 / B + 1 / C is less than 0

It is known that a, B and C satisfy a + B + C = 0 and ABC = 8. It is proved that 1 / A + 1 / B + 1 / C is less than 0

Proof: because a + B + C = 0
So (a + B + C) ^ 2 = 0
Write a ^ 2 + B ^ 2 + C ^ 2 + 2Ab + 2Ac + 2BC = 0
a^2+b^2+c^2=-2ab-2ac-2bc
From ABC = 8, we can deduce that the left side of the equation must be greater than 0, because there is no 0
Then AB + AC + BC can be summed up on the right side of the equation