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證明:因為a+b+c=0 所以(a+b+c)^2=0 拆開來寫a^2+b^2+c^2+2ab+2ac+2bc=0 a^2+b^2+c^2=-2ab-2ac-2bc 由abc=8可以推出等式左邊肯定是大於0的,因為沒有0的存在 那麼等式右邊可以總結出ab+ac+bc
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