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a+b+c=0 則a+b=-c a+c=-b b+c=-a 原式=a/b+a/c+b/c+b/a+c/a+c/b+3 =(a+b)/c+(a+c)/b+(b+c)/a+3 =-c/c+(-b)/b+(-a)/a+3 =-1-1-1+3 =0
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