Given that a + B + C = 0 and ABC ≠ 0, the value of a (1 △ B + 1 △ C) + B (1 △ C + 1 △ a) + C (1 △ a + 1 △ b) + 3 is calculated

Given that a + B + C = 0 and ABC ≠ 0, the value of a (1 △ B + 1 △ C) + B (1 △ C + 1 △ a) + C (1 △ a + 1 △ b) + 3 is calculated

a+b+c=0
Then a + B = - C
a+c=-b
b+c=-a
Original formula = A / B + A / C + B / C + B / A + C / A + C / B + 3
=(a+b)/c+(a+c)/b+(b+c)/a+3
=-c/c+(-b)/b+(-a)/a+3
=-1-1-1+3
=0