Contact us
Choose a category below so we can get back to you as quickly as possible.
a=b=1 c=-2 則a(b+c)+b(a+c)+c(a+b)=-6 a=1 b=2 c=-3 a(b+c)+b(a+c)+c(a+b)=-14 事實上a(b+c)+b(a+c)+c(a+b)=-a^2-b^2-c^2 所以條件不足值有無窮多個
We and our partners use cookies and other technologies to analyze traffic and optimize your experience. View more info and control your cookies settings at any time in our Cookies Policy.