In the triangle ABC, if three sides are known to be continuous positive integers, The cosine value of the maximum angle is - 1 / 4. Find the maximum area of the parallelogram with the maximum angle as the inner angle and the sum of the two sides of the angle as 4

In the triangle ABC, if three sides are known to be continuous positive integers, The cosine value of the maximum angle is - 1 / 4. Find the maximum area of the parallelogram with the maximum angle as the inner angle and the sum of the two sides of the angle as 4

cos=-1/4
(sin)^2+(cos)^2=1
So the sine of this angle is 15 / 4
On both sides are ab
A + B = 4 because triangle area = 1 / 2absinc
So parallelogram = absinc = AB * √ 15 / 4
a+b=4,b=4-a
So 0