If the sequence {an} satisfies A1 = 2 and an + an-1 = 2n + 2N-1, Sn is the sum of the first n terms of the sequence {an}, then log2 (s2012 + 2) is equal to () A. 2013B. 2012C. 2011D. 2010

If the sequence {an} satisfies A1 = 2 and an + an-1 = 2n + 2N-1, Sn is the sum of the first n terms of the sequence {an}, then log2 (s2012 + 2) is equal to () A. 2013B. 2012C. 2011D. 2010

∵ an + an-1 = 2n + 2N-1, ∵ an = 2n, that is, the sequence {an} is an equal ratio sequence of common ratio q = 2, then Sn = 2 · (1 − 2n) 1 − 2 = 2n + 1-2, then s2012 = 22013-2, then log2 (s2012 + 2) = log222013 = 2013, so select: a

Elden Ring Premiere

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