Let the first n terms of sequence {an} and Sn = 2an-2 ^ n (1) prove that {a (n + 1) - 2An} is the general term of finding {an} from the equal ratio sequence (2) The second question doesn't matter. Try to do it

Let the first n terms of sequence {an} and Sn = 2an-2 ^ n (1) prove that {a (n + 1) - 2An} is the general term of finding {an} from the equal ratio sequence (2) The second question doesn't matter. Try to do it

1) Sn = 2an-2 ^ ns (n + 1) = 2A (n + 1) - 2 ^ (n + 1) is subtracted to get a (n + 1) = 2A (n + 1) - 2 ^ (n + 1) - 2An + 2 ^ n. A (n + 1) - 2An = 2 ^ n is reduced to a (n + 1) - 2An = 2 ^ n, which indicates that {a (n + 1) - 2An} is an equal ratio sequence 2) a (n + 1) - 2An = 2 ^ N2 (an-2a (n-1)) = 2 * 2 ^ (n-1) = 2 ^ N2 ^ 2 (a (n-1) - A (n-2)) = 2 ^ 2 * 2 ^ (n-2) = 2 ^ n... 2 ^