Weida's law for solving equations x. Y is the square of the equation x - 4x + 2 = 0 The value of the square of (X-Y) And the value of X / y + Y / X

Weida's law for solving equations x. Y is the square of the equation x - 4x + 2 = 0 The value of the square of (X-Y) And the value of X / y + Y / X

By means of Weida's law x + y = 4xy = 2 and (X-Y) & sup2; = (x + y) & sup2; - 4xy, we substitute the values of X + y and XY into the above formula = 4 & sup2; - 4 × 2 = 16-8 = 8x / y + Y / x = (X & sup2; + Y & sup2;) / xy and X & sup2; + Y & sup2; = (x + y) & sup2; - 2XY = 16-4 = 12, so x / y + Y / x =