Let three mutually unequal rational numbers be expressed in the form of 1, a + B, a, or 0, B / A, B, then B-A =?

Let three mutually unequal rational numbers be expressed in the form of 1, a + B, a, or 0, B / A, B, then B-A =?

1, a + B, the number of a is 0
So maybe a + B = 0 or a = 0
But if a = 0, B / A is meaningless, so a + B = 0
If you look at 0, B / A, one of B is 1
Obviously, B / a = - 1 is obtained from a + B = 0
So it's only possible that B = 1
At this time, all of them are calculated, a = - 1, B = 1
So B-A = 2

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