As shown in the figure, it is known that the numbers a, B and C corresponding to points a, B and C on the number axis are not 0, and C is the midpoint of ab. if [a + b] - [a-2c] + [b-2c] - [a + b-2c] =0, then the position of origin 0 is () A. On line AC, B. on line Ca, C. on line BC, D. on line CB Is the absolute value sign

As shown in the figure, it is known that the numbers a, B and C corresponding to points a, B and C on the number axis are not 0, and C is the midpoint of ab. if [a + b] - [a-2c] + [b-2c] - [a + b-2c] =0, then the position of origin 0 is () A. On line AC, B. on line Ca, C. on line BC, D. on line CB Is the absolute value sign

If C is the midpoint of AB, then a + B = 2c, so
1,a+b-2c=0--->|a+b-2c|=0
2,a-2c=-b--->|a-2c|=|-b|=|b|
3,b-2c=-a--->|b-2c|=|-a|=|a|
Therefore, the original formula = | a + B | - | B | + | a | - 0 = 0
--->|a+b|=|b|-|a|
Because | a + B | > 0 --- > A, B is different sign, and | B | > | a |, is | ob | > | OA |, so the point O is between a and C