Can you make two triangles with three, three, four centimeters long and three, four, six centimeters long?

Can you make two triangles with three, three, four centimeters long and three, four, six centimeters long?

Fine
The sum of the two sides of the triangle is greater than the third side, and the difference between the two sides is less than the third side

Take one 40 cm long [math problem]
Cut a cuboid 40 cm long, 12 cm wide and 16 cm high into four identical cubes
1. How many square centimeters can its surface area increase at most?
2. At least how many square centimeters can be added?

Max = 40x16x6 = 3840 square centimeter
Minimum = 12x16x4 = 768 cm2

How to spell length unit and weight unit in English

Fathom long measure unit of length
Unit of weight; hundredweight; maund; pound; ser
hectogram ;kip ;unit of weight
unit of weight
unit of weight
Please go to ICIBA English for details

If {3x + 2Y + 2Z = 140, 5x + 3Y + 3Z = 220, then x =? Y =? Z =?

3x+2y+2m=140 ①
5x+3y+3m=220 ②
It can be obtained by combining 1 × 3 and 2 × 2,
9x+6y+6m=420 ③
10x+6y+6m=440 ④
③ - 4, x = 20
Bring x = 20 into ① and ②
I have to,
60+2y+2m=140
100+3y+3m=220
The direct solution is y + M = 40
Ψ x + y + M = 40 + 20 = 60 (M is Z)

How to calculate 111 * 23 simply

111* 23
=(1+10+100)*23
=1*23+10*23+100*23
=23+230+2300
=2553

As shown in the figure, in ⊙ o, diameter AB = 10, chord CD ⊥ AB, perpendicular foot is point E, if OE = 3, then CD=______ ．

Connecting OC, ∵ diameter AB = 10, ∵ OC = 12ab = 5, ∵ CD ⊥ AB, OE = 3, ∵ CD = 2ce, in RT △ OCE, CE2 + oe2 = oc2, that is CE2 + 32 = 52, the solution is CE = 4, ∵ CD = 2ce = 2 × 4 = 8

Urgent, ten way multiplication and ten way division

29 by 58 74 by 14 49 by 54 56 by 23 58 by 151
153 by 51 56 by 541 23 by 64 57 by 48 425 by 12
140 in 20, 80 in 40, 300 in 60, 270 in 30, 350 in 70
90 divided by 30 180 divided by 20 420 divided by 60 69 divided by 23 324 divided by 81

As shown in the figure, in △ ABC, the vertical bisector De of AB intersects AB at D and BC at E. if CE = 3cm, calculate the length of be

∵ - C = 90 °, ∵ BAC = 60 °, ∵ B = 90 ° - 60 ° = 30 °, ∵ De is the vertical bisector of AB, ∵ AE = be, ∵ BAE = ∵ B = 30 °, ∵ CAE = ∵ BAE, ∵ de = CE = 3cm, and ∵ B = 30 °, ∵ be = 2DE = 2 × 3 = 6cm

777 * 5 + 999 * 7 + 222, which method is more convenient?

777*5+999*7+222
＝111×7×5×+111×9×7+111×2
＝111×35+111×63+111×2
＝111×（35+63+2）
＝111×100
＝11100

Solving equation 2 (X-2) (x + 3) - (2x-5) (x-1) = 3x + 7

Just unfold this one
2*（x^2+x-6）-(2*x^2-7X+5)-3x-7=0
The results are as follows
6X=24
x=4
It should be right
hey.