How much power is used for 100 m 1 square copper wire

How much power is used for 100 m 1 square copper wire

Safe operating current: 20 A. allowable operating current: 52 A. fusing current: 104 a
Power calculation of electric appliance: voltage at the end of line (connected to the end of electric appliance) × current = power
Total power calculation: line power + electrical power

As shown in the figure, a 10m long ladder AB leans against the wall. The vertical distance between the top of the ladder and the ground is 8m. If the top of the ladder slides 2m, does its bottom slide 2m? Please explain by calculation

Reason: in RT △ ACB, BC2 + ac2 = AB2, BC = 102 − 82 = 6, (2 points) and ∵ AA ′ = 2, ∵ AC = 6, in RT △ a ′ CB ', B ′ C = 8, (2 points) ∵ BB ′ = 2, ∵ bottom sliding 2m. (1 point)

A 10 ohm constant value resistor connected to a 6V power supply, how much heat is released in 10s? How much electric energy is consumed?

I=U/R=6/10=0.6
Q=I*IRT=36J
W=UIT=36J

63 × 67 = 6 × (6 + 1) × 100 + 3 × 7 = 4200 + 21 = 4221 692 × 698 = 69 × (69 + 1) × 100 + 2 × 8 = 483000 + 16 = 483016
What is the sum of the numbers in each digit of the two factors? What are the characteristics of the numbers in the other digits? What are the algorithms

The sum of the numbers in one digit is 0, and the other digits are equal
The sum of two digits and the multiplication of two factors with the same number of other digits is equal to the sum of the remaining digits multiplied by this number plus 1 times 100 plus two digits
For example, AB * a (10-B) = a (a + 1) * 100 + B (10-B)

In the circuit shown in the figure, the electromotive force E of the battery is 9.0V, the internal resistance R is 2.0ohm, the fixed resistance R1 is 1.0ohm, and R2 is the variable resistance,
The resistance can be adjusted in the range of 0-10 Ω. When R2 = -, R1 consumes the most electric power. When R2 = -, R2 consumes the most electric power
(R1, R2 are in series in the circuit)

R2=0
R2=3

As shown in the figure, for the "pyramid" arrangement composed of natural numbers, first observe its rule, and then guess the 26th number from left to right in the 25th row
one
2 3 4
5 6 7 8 9
10 11 12 13 14 15 16...

The number s (n) = 2 * n-1, the last number f (n) = f (n-1) + 2 * n-1 = n = n * NF (n) = f (n-1) + 2 * n-1f (n-1) = f (n-2) + 2 * (n-1) - 1. F (1) = 2 * (1) - 1 = = = > F (n) = 2 * n-1 + 2 * (n-1) - 1 +... + 2 * (2) - 1 + 2 * (1) - 1

The voltage remains unchanged. When the lamp with a resistance of 242 Ω is connected, the current in the circuit is fed to 0.91a. If the circuit iron with a resistance of 165 Ω is changed, the current in the circuit will be
The voltage remains the same. When the lamp with a resistance of 242 Ω is connected, the current in the circuit will be fed to 0.91a. If the circuit iron with a resistance of 165 Ω is changed, how much current in the circuit will become?
[Note: to draw circuit diagram]
Picture:
Known:
Ask for:

Known:
Lamp r = 242 Ω, current I = 0.91a
Calculate the power supply voltage:
U＝RI＝242×0.91≈220(V)
If the circuit iron with resistance of 165 Ω is changed, the current in the circuit:
I＝U/R＝220/165≈1.33(A)

5 × 17 of 8, 2 of 0.6 × 7 + 3 × 7 of 5
5 / 8 × 17 0.6 × 7 / 2 + 3 / 5 × 7 / 2
= =
= =
= =

5 / 8 × 17
=5 / 8 × (16 + 1)
=5 / 8 × 16 + 5 / 8
=5 × 2 + 5 / 8
=10 + 5 / 8
=10 and 5 / 8
2 of 0.6 × 7 + 3 of 5 × 7
=3 / 5 × 2 / 7 + 3 / 5 × 2 / 7
=3 / 5 × 2 / 7
=6 / 35 × 2
=12 out of 35

What instrument is needed to measure resistance with ammeter and voltmeter in the experiment, what is the way to change the voltage at both ends of conductor
Let's talk about how to draw the circuit diagram of measuring resistance with voltmeter and ammeter

Instruments: ammeter, voltmeter, sliding rheostat, DC power supply, constant resistance
Change the voltage by moving the slide of the sliding rheostat

-The cube of 5x - (2m-1) the square of X + (2-3n) X-1. For the cubic binomial test of X, find the value 1 of M + 2n
Good bonus points, 100

∵ - 5x & sup3; - (2m-1) x & sup2; + (2-3n) X-1 is a cubic binomial of X,
∴-（2m-1）=0 m=1/2
2-3n=0 n=2/3
m＋2n=2/3＋2×1/2=5/3