English translation 180 degree honeymoon 2F 180 degree sea view honeymoon room 3-5f Super sea view Honeymoon Room 6F Sea view leisure mahjong room 2F 280 degree all sea view romantic honeymoon suite 6F

English translation 180 degree honeymoon 2F 180 degree sea view honeymoon room 3-5f Super sea view Honeymoon Room 6F Sea view leisure mahjong room 2F 280 degree all sea view romantic honeymoon suite 6F

180 degree honeymoon 2F
180 degree viewing honeymoon room 2 F
180 degree sea view honeymoon room 3-5f
180-degree sea view honeymoon room 3-5 F
Super sea view Honeymoon Room 6F
Super seaview honeymoon big bed room 6 F
Sea view leisure mahjong room 2F
Seaview leisure mahjong room 2 F
280 degree all sea view romantic honeymoon suite 6F
280 degrees seaview romantic honeymoon suites 6 F

English translation
Exquisite big bed room
Deluxe Twin / King Room
Urban landscape Twin / King Room
Executive Room
Executive Suite
We don't have any culture. Thank you first

Exquisite bed rooms
Deluxe Twin / King Room
Urban landscape Twin / King Room
Executive Room
Executive Suite

How to calculate 222 times 999?
Test papers

222*(1+999)-222=221778
Take 1000 222s, add them and subtract one 222

Solve the equation x (3x-4) - 7 = 2 (x ^ 2-2) + 2x

x(3x-4)-7=2(x^2-2)+2x
Remove the brackets to get 3x ^ 2-4x-7 = 2x ^ 2-4 + 2x
Transfer and merge similar items to get x ^ 2-6x-3 = 0
The formula is: (x-3) ^ 2 = 12
Both sides square at the same time: x-3 = ± √ 12
X = 3 + 2 √ 3 or x = 3-2 √ 3

Conversion of degrees, minutes and seconds
How to convert degrees, minutes and seconds into degrees?
Using 56 ° 25 ′ 12 ″

Divide by 60, (56 + 25 / 60 + 12 / 3600) degrees

Chord length AB = under the root sign (x2-x1) ^ 2 + (y2-y1) ^ 2 = under the root sign (1 + K ^ 2) (x2-x1) ^ 2 please explain in detail how to get the one after the equal sign? K is

Because X1 = kx1, X2 = kx2
So substitute X1 = kx1, X2 = kx2 into (x2-x1) ^ 2 + (y2-y1) ^ 2 = (x2-x1) ^ 2 + (kx2-kx1) ^ 2 = (1 + K ^ 2) (x2-x1) ^ 2
So chord length AB = under root sign (x2-x1) ^ 2 + (y2-y1) ^ 2 = under root sign (1 + K ^ 2) (x2-x1) ^ 2

-How much is 6 times 11 and 11 out of 12

Let a = (3 / 2, SiNx), B = (cosx, 1 / 3), and a / / B, then the acute angle X is?

The necessary and sufficient condition for a / / B is 3 / 2 × 1 / 3-sinx × cosx = 0 (1 / 2) sin2x = 1 / 2
sin2x=1 x=45°

o. What's 55

It's 11 / 20

The point P is a moving point on the parabola C1: x ^ 2 = 2PY. Two tangent lines of circle C2: x ^ 2 + (Y-3) = 1 intersect Y-axis at two points a and B. It is known that the distance from the fixed point Q (1,13 / 4) to the collimator of parabola C1 is 7 / 2
(1) It is proved that the line PA and Pb are not perpendicular. (2) if the line AB is bisected by the line PQ, the coordinates of point P are obtained

(1) The distance between Q (1,13 / 4) and parabola C1: y = - P / 2 is 13 / 4 + P / 2 = 7 / 2, P = 1 / 2,
Let P (T, T ^ 2) be a moving point on parabola C1: x ^ 2 = y,
Make the tangent of circle C2: x ^ 2 + (Y-3) ^ 2 = 1 through P: Y-T ^ 2 = K (x-t), that is, kx-y + T ^ 2-kt = 0,
The distance from the center C2 (0,3) to the tangent = | - 3 + T ^ 2-kt | / √ (k ^ 2 + 1) = 1,
The square is (- 3 + T ^ 2-kt) ^ 2 = k ^ 2 + 1,
(T ^ 2-1) k ^ 2-2t (T ^ 2-3) K + (T ^ 2-3) ^ 2-1 = 0, ①
If the product of slopes of two tangent lines k1k2 = [(T ^ 2-3) ^ 2-1] / (T ^ 2-1) = - 1,
Then (T ^ 2-3) ^ 2-1 = 1-T ^ 2,
The results show that T ^ 4-5t ^ 2 + 7 = 0, there is no real solution,
The line PA is not perpendicular to Pb
(2) The tangent intersects Y-axis at a (0, T ^ 2-k1t), B (0, T ^ 2-k2t),
From (1), K1 + K2 = 2T (T ^ 2-3) / (T ^ 2-1), the,
The midpoint of AB is m: XM = 0, YM = T ^ 2-T (K1 + K2) / 2 = T ^ 2-T ^ 2 (T ^ 2-3) / (T ^ 2-1) = 2T ^ 2 / (T ^ 2-1),
P, m and Q are collinear when line AB is bisected by line PQ,
The slopes of PQ and MQ are equal, that is, (T ^ 2-13 / 4) / (t-1) = 13 / 4-2t ^ 2 / (T ^ 2-1),
Multiply both sides by 4 (T ^ 2-1) to get (4T ^ 2-13) (T + 1) = 13 (T ^ 2-1) - 8t ^ 2,
4t^3+4t^2-13t-13
-5t^2 +13=0,
4T ^ 3-T ^ 2-13t = 0, T1 = 0, t2,3 = (1 Soil √ 209) / 8,
The coordinates of point P are (0,0), ((1 + √ 209) / 8, (105 + √ 209) / 32), (1 - √ 209) / 8, (105 - √ 209) / 32)