If the odd function f (x) defined on R satisfies f (2x) = - 2F (x), f (− 1) = 12, then the value of F (2) is () A. -1B. -2C. 2D. 1

If the odd function f (x) defined on R satisfies f (2x) = - 2F (x), f (− 1) = 12, then the value of F (2) is () A. -1B. -2C. 2D. 1

∵ f (x) the odd function defined on R ∵ f (- 1) = - f (1) ∵ f (1) = - f (- 1) = - 12 and ∵ f (2x) = - 2F (x) let x = 1, then f (2) = - 2F (1) = - 2 × (− 12) = 1, so D is chosen

The number whose absolute value is equal to √ 2-1 is
Root 2-1

The number whose absolute value is equal to √ 2-1 is √ 2-1 or 1 - √ 2, which is not a process

Definition field of logarithmic function
Given that the definition field of function f (x) = log2 (MX ^ 2 + MX + 1) is r, the value range of real number m is ()
Such a question, why m can be equal to 0, then its domain of definition is not only 1?

For example, log2 (x) defines that the domain x is greater than 0
So the problem is that MX ^ 2 + MX + 1 is greater than 0,
If the domain of F (x) = log2 (MX ^ 2 + MX + 1) is r, then MX ^ 2 + MX + 1 is always greater than 0
So M & sup2; - 4m is less than or equal to 0, so the range of M can be obtained
When m = 0, f (x) = log2 (1) = 0
There can be only one element in the domain, so it doesn't matter if the domain has only 1

When calculating 18 divided by (- 0.9), first determine the sign of quotient is -. When calculating the absolute value of quotient is-----

When calculating 18 divided by (- 0.9), the sign of the quotient is negative, and the absolute value of the quotient is 20
I'm very glad to answer your questions. Skyhunter 002 will answer your questions
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Let f (x) be an odd function defined on R. if x belongs to (0, positive infinity), f (x) = LG (x), find the analytic expression of F (x)

The odd function of F (x) defined on R
f(x)=-f(-x)
x> 0, f (x) = lgx
x0
f(x)=-f(-x)=-lg(-x)

The function f (x) = ax + B / 1 + X * x is an odd function defined on (- 1,1), and f (1 / 2) = 2 / 5
(1) Determining the analytic expression of function f (x)
(2) Prove that f (x) is an increasing function on (- 1,1) by definition
(3) Solving inequality: F (t-1) + F (T)

(1)
From the known f (- x) = - f (x)
∴-ax+b/(x^2+1)=-ax-b/(x^2+1)
The solution is b = - 1
Then f (x) = AX-1 / (x ^ 2 + 1)
And f (1 / 2) = 2 / 5
∴2/5=a/2-1/(1+1/4)
The solution is a = 12 / 5
∴f(x)=12x/5-1/(x^2+1)
(2)
Set - 1

A number is added, subtracted, and divided by itself. The sum, difference, and quotient are added again. The sum is 8.6. What is the number?

This number is x; from the meaning of the paper, you can get: (x + X + X + X (x + x) + (x-x-x) + (x-x-x) + (x-x-x-x) + (x-x-x (x-x) + (x-x-x) + (x-x-x) + (x-x-x (x-x-x) + (x-x-x) + (x-x-x \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\- 1 = 8.6-1, & nbsp; & nbsp; & nbsp; & nbsp;                   2x=7.6，                   2x÷2=7.6÷2，                   &X = 3.8. A: this number is 3.8

If f (2) = 3, find f (1); f (0) = a, find f (a) (2) let there be only one real root x, f (x) = x, find the expression of F (x)

It's so hard

There are two points AB on the number axis, where the corresponding point of a is a and the corresponding number of B is 1. We know that the distance between a and B is less than 3, and find whether the distance between - 3,0,4 and B is less than 3

There are two points AB on the number axis, where the corresponding point of a is a, and the corresponding number of B is 1. We know that the distance between a and B is less than 3, and there are two points
-2

In this paper, the square of the equation AX - BX = mx-n-bx - CX (a + B + C is not equal to 0) is transformed into the general form of quadratic equation with one variable,

The square of ax - BX = the square of mx-n-bx - the square of CX
Square of ax - BX MX + N + square of BX + square of Cx = 0
(a+b+c)x^2-(b+m)x+n=0