We know that the polynomial x ^ 3-2x ^ 2 + AX-1 is divided, the division is BX-1, the quotient is x ^ 2-x + 2, and the remainder is 1,

We know that the polynomial x ^ 3-2x ^ 2 + AX-1 is divided, the division is BX-1, the quotient is x ^ 2-x + 2, and the remainder is 1,

x^3-2x^2+ax-1=（bx-1）（x^2-x+2）+1
（bx-1）（x^2-x+2）+1
=bx^3-bx²+2bx-x²+x-2+1
=bx^3-(b+1)x²+(2b+1)x-1
So:
b=1；
a=2b+1=2+1=3；
x^3-2x^2+ax-1=x^3-2x²+3x-1.
The polynomial is: x ^ 3-2x & # 178; + 3x-1

Given the polynomial x 3-2x + AX-1 divided by B X-1, the quotient is x 2-x + 2, the remainder is 1, find the value of a and B

From the meaning of the title, we can see that x3-2x + AX-1 = (BX-1) × (x2-x + 2) + 1, which is sorted out as follows: x3-2x2 + AX-1 = BX3 + (- B-1) x2 + (2B + 1) X-1, х B = 1, a = 2B + 1, х a = 3, B = 1

In the following algebraic expressions: 1 / 2 * AB, 1 / 2 * a + B, the square of AB + B + 1, a + 3, 2 / A + 1 / 2, the square of x-x + 1, how many polynomials are there?

There are five Polynomials: 1 / 2 * a + B, the square of AB + B + 1, a + 3, 2 / A + 1 / 2, and the square of x-x + 1

If the real numbers a, B and C are in the sequence of equal difference numbers, and a + B + C = 12, and a, B and C + 2 are in the sequence of equal ratio numbers, then the set of values of a is formed

According to the meaning of the question: a + B + C = 12b ^ 2 = a (c + 2) the median of the equivariance is: (a + C) / 2 = Ba + C = 2b2b + B = 12b = 4. A + C = 8C = 8-a16 = a (8-A + 2) 16 = a (10-A) 16 = 10a-a ^ 210a-a ^ 2-16 = 0A ^ 2-10a + 16 = 0 (A-2) (A-8) = 0a1 = 2, A2 = 8c1 = 6, C2 = 0, so the sequence is 2,4,6 or 8,4,0

How to calculate the process
That is to say. A * (A-10) + 25 = 0, a = how much? You can see that the answer is 5. But I don't know how to calculate it-

That is a & # 178; - 10A + 25 = 0
(a-5)²=0
a-5=0
a=5

In the isosceles trapezoid ABCD, ad is parallel to BC, ab = DC = a, ∠ B = 60 °, AC bisects ∠ BCD, and calculates the trapezoid perimeter

From the known conditions
∠ACB=30°
AD=DC=AB=a
In △ ABC, cab = 180 ° - 60 ° - 30 ° = 90 °
So BC = 2Ab = 2A
Then the trapezoid perimeter = 2A + A + A + a = 5A

Set * as an operation symbol, a * b = AB Ba, and try to calculate the value of 4 * (3 * 2)

How can there be two variables on the left and four variables on the right? A is the same as a? If a is the same, it will be 0. Let me do it for you according to my understanding: A is the same as a, ab = 10xa + BX1, that is to say, ab is a connection, not a multiplication. Then: 4 * (3 * 2) = 4 * (32-23) = 4 * 9 = 49-94 = - 45

If a square matrix of order n is known to be similar to a diagonal matrix, then
A. A has n different eigenvalues
B. A must be a real symmetric matrix of order n
C. A has n linearly independent eigenvectors
D. The eigenvectors of a belong to different eigenvalues are orthogonal

C correct
If a is wrong and a has n different eigenvalues, then a is similar to a diagonal matrix
B. It's not right
D. Not necessarily

Put the nine numbers 1,2,3,4,5,6,7,8,9 in the box to make the equation hold_ =1/2×_ _ _ =1/3×_ _ _

273,546,819

Matrix multiplication
To find the multiplication process of matrix, we should point out the multiplication process of each element
Please use 3 * 3 matrix to do demonstration, multiplication matrix with 3 * 3, note: I am only a junior high school student, please make it clear!!!!!

We can use 2 * 3 and 3 * 4 as examples. That is to say, a b c d e f * a B C D E F G H I j k l can find the first three columns and the second three rows with equal number of rows and columns respectively. Then