The sum of a prime number and five times of itself is 30. What is the prime number?

The sum of a prime number and five times of itself is 30. What is the prime number?

30÷（5+1）=30÷6=5

In prime numbers within 30, the sum of two prime numbers is the common group of prime numbers

Five groups
2 3、2 5、2 11、2 17、2 29.

How to calculate 8 2 3 7 9 as 4 (it must be calculated in numerical order)

8-2*3-7+9=4

If the solution of the equation LNX = 6-2x is x0, then the largest integer k =

Let f (x) = LNX + 2x-6
Because f (2) = ln2-20
SO 2

What is the sin1 / X image like?

It is very different from the image of y = SiNx. It is an oscillation curve with variable frequency. The closer to the origin, the higher the frequency, as shown in the figure

2X + (10-x) * 4 = 36,

Original formula = > 2x + 40-4x = 36
===> -2x+40=36
===> 2x=40-36=4
===> x=2

2 × 3 / 1 + 3 × 4 / 1 +
1 of 2 × 3 + 1 of 3 × 4 + 1 of 4 × 5 +. + 1 of 8 × 9 + 1 of 9 × 10
1 / 3 + 1 / 15 + 1 / 35 + 1 / 63 + 1 / 99 + 1 / 143
5x of 6-3 of 4 = 2x of 7

1)
=1/2-1/3+1/3-1/4+…… +1/9-1/10
=1/2-1/10
=2/5
2)=1/1×3+1/3×5+…… +1/11×13
=1/2(2/1×3+2/3×5+…… +2/11×13)
=1/2(1-1/3+1/3-1/5+…… +1/11-1/13)
=1/2(1-1/13)
=6/13
3）
Go to the denominator
70x-63=28x
42x=63
∴x=3/2

Draw a (2,3) B (- 3, - 2) C (4,1) three points in the plane rectangular coordinate system as shown in the figure, and connect a, B, C three points in turn with line segments
Can you work out its area?
(it's better to have written narration ~)
We should not copy what we have on the Internet, which is not suitable for our junior high school students, and I don't understand,
For example:
c=|AB|=√[(2+3)^2+(2+3)^2]=5√2
b=|AC|=√[(4-2)^2+(1-3)^2]=2√2
a=|BC|=√[(4+3)^2+(1+2)^2]=√58
a^2=b^2+c^2
S=bc/2=5√2*2√2/2=10

This is the knowledge of junior high school! C = | ab | = √ [(2 + 3) ^ 2 + (2 + 3) ^ 2] = 5 √ 2 (distance formula between two points! Square root of difference between abscissa and ordinate) B = | AC | = √ [(4-2) ^ 2 + (1-3) ^ 2] = 2 √ 2 (ditto) a = | BC | = √ [(4 + 3) ^ 2 + (...)

What is 15 × (230-30 △ 5) equal to?

15×（230-30÷5）=15×（230-6）
=15×224
=3360

If the slope of the linear equation 3x + 2y-6 = 0 is K and the intercept on the Y axis is B, then ()
A. k=-23，b=3B. k=-32，b=3C. k=-23，b=-3D. k=-32，b=-3

From the linear equation 3x + 2y-6 = 0 to the oblique section: y = − 32x + 3, we can get the slope k = - 32, and the intercept on the Y axis is b = 3