Given that the equation of line L is x-2y-6 = 0, find the slope of line L and its intercept on y-axis It's a process

Given that the equation of line L is x-2y-6 = 0, find the slope of line L and its intercept on y-axis It's a process

Transform y = x / 2-3, intercept is 3, slope is 2

f(x)=(sinx+cosx)^/(2+2sin2x-cos^2x)
^It means square

f(x)=(sinx+cosx)^/(2+2sin2x-cos^2x)
=(sin^x+cos^x+2sinxcosx)/(1++2sin2x+1-cos^2x)
=1+sin2x/(sin^2x+2sin2x+1)
=1+sin2x/(1+sin2x)^
=1/(1+sin2x)

If the line y = - 2x-1 intersects with the line y = 3x + m in the third quadrant, please make sure that the value range of the real number m is written carefully

Simultaneous y = - 2x-1
y=3x+m
The solution is x = (- m-1) / 5
y=（2m-3）/5
The intersection is in the third quadrant
x=（-m-1）/5

F (x) is an odd function on R. if x > 0 is, f (x) = - 2x ^ 2 + 3x + 1, find the analytic expression of F (x)

Set x0
So f (- x) = - 2x ^ 2-3x + 1
Because it's an odd function,
So f (x) = - f (- x) = 2x ^ 2 + 3x-1

The edge length of a cube is 1.5 * 10 to the second power cm. The volume of the cube is expressed in the form of a * 10 to the nth power (1 ≤ a ≤ 10, n is a positive integer)?
calculation:
1.2 times [- 4] times 0.125
2. 2011 power of [- 8] times 2012 power of 0.125

1. The edge length of a cube is 1.5 * 10 to the second power cm, and the volume of the cube is expressed in the form of a * 10 to the nth power (1 ≤ a ≤ 10, n is a positive integer)?
The volume of cube = edge length & # 179; = (1.5 * 10 to the second power cm) &# 179; = 3.375 * 10 to the sixth power CM & # 179;
The power of 2013 of 2.2 multiplied by the power of 2013 of [- 4] multiplied by the power of 2013 of 0.125
=The power of [2 times (- 4) times 0.125]
=The power of (- 1)
=-1
3. 2011 power of [- 8] times 2012 power of 0.125
=The 2011 power of [- 8] multiplied by 0.125 and the 2011 power multiplied by 0.125
=The 2011 power of [(- 8) times 0.125] times 0.125
=The 2011 power of (- 1) is multiplied by 0.125
=-0.125

It is known that the set M is a set of functions f (x) satisfying the following properties: there exists a non-zero constant K, for any x ∈ D, the equation f (KX) = K2 + F (x) holds. (1) try to judge whether the first-order function f (x) = ax + B (a ≠ 0) belongs to the set M; (2) prove that f (x) = log2x belongs to the set M, and write a constant K satisfying the condition

(1) If the equation f (KX) = K2 + F (x) is constant, then a (K − 1) x − K2 = 0 is constant, ∵ a ≠ 0 ∵ K − 1 = 0k2 = 0, ∵ there is no non-zero constant K, ∵ the function f (x) = ax + B (a ≠ 0) does not belong to the set M. (2) prove that for any x ∈ (0, + ∞), f (KX) = log2 (KX), ∵ K2 + log2x

It is known that a is the sum of the opposite number of 7 and 12, and B is 14 less than the absolute value of - 10
(1) Finding the value of A-B and B-A
(2) According to the result of (1), can you guess the relationship between A-B and B-A?
How to write the second question

(1)A=-7+12=5
B+14=10
B=-4
5-(-4)=9
-4-5=-9
(2) Because 9 = - (- 9)
So a and B are opposite to each other

Logarithmic function: known (1 / 2) ^ x

Because (1 / 2) ^ X0

Hello! How to simplify the absolute value and opposite number of many symbols?
For example: the absolute value of negative 3-1

Follow a principle: the same sign is positive, different sign is negative: such as - (+ 2), a positive and a negative is different sign, Gude - 2, - 2, two negative signs belong to the same sign, Gude 2. Another way of understanding: negative means opposite quantity, positive means unchanged, such as - (+ (- 1)), the positive sign before negative one means itself, reduced to - (- 1), and negative means opposite

Is f (x) = LG [(1-x) / (1 + x)] an odd function?
The answer in the book is "odd function", but its domain of definition is not symmetric about the origin

Prove: the function f (x) = LG [(1-x) / (1 + x)] is an odd function
Certificate:
First, define the domain
Because (1-x) / (1 + x) > 0,
So (x-1) / (x + 1)