Fill the nine numbers - 2, - 1, 0, 1, 2, 3, 4, 5 and 6 into the nine spaces of the square matrix, so that the sum of the three numbers in the horizontal, vertical and diagonal angles is 6

Fill the nine numbers - 2, - 1, 0, 1, 2, 3, 4, 5 and 6 into the nine spaces of the square matrix, so that the sum of the three numbers in the horizontal, vertical and diagonal angles is 6

As shown in the figure

The method of addition, subtraction and elimination for quadratic equation of two variables
1.{3m+b=11 2.{0.6X+0.4y=11 3.{4f+g=15 4.{1/2X+3y=-6
{-4m-b=11 {0.2X-0.4y=2.3 {3g-4f=-3 {1/2X+y=2
5.{3(X-1)=y+5 6.{2u/3+3X/4=1/2
{5(y-1)=3(x+5) {4u/5+5X/6=7/15
I will hand in my homework tomorrow

1.m=-22,b=77
3.f=3,g=3
4.x=12,y=-4
5.x=5,y=7
6.u=-3/2,x=2

How to calculate the third question on page 54 of the first volume of primary school mathematics homework

195 divided by 13 = 15 (days) 15 times 16 = 240 (Times) rainy days: (240-195) divided by (16-11) = 9 (days) sunny days: 15-9 = 6 (days)

A rectangular reservoir is 25 meters long, 16 meters wide and 4 meters deep. It needs to be plastered with cement around and at the bottom. How many square meters is the area of plastering cement?

25*16+(25*4+16*4)*2
=400+164*2
=400+328
=728 square meters

The quotient of a divided by B is 1.4, and the simplest integer ratio of a and B is______ ．

Because the number A / b = 1.4 = 75, the number A: B = 7:5

The area of the bottom of the column is 18 square decimeters, the volume is 9 cubic decimeters, what is the height?

9 △ 18 = 0.5 decimeter

Divide a number by 9, quotient 3 and remainder 3, and find the solution of the equation

30

The bottom of an open iron box is a square with a circumference of 16 decimeters and a height of 5 decimeters. How many decimeters of iron sheet does it need to make 100 such iron boxes?

Because the bottom of the iron box is a square, and the perimeter of the bottom is 16 decimeters, the length and width of the iron box are equal to 4 decimeters, and the area of the iron sheet is required: [(4 × 4 + 4 × 5 + 5 × 4) × 2-4 × 4] × 100, = [(16 + 20 + 20) × 2-16] × 100, = (56 × 2-16) × 100, = (112-16) × 100, = 96 × 100

The bottom radius of a cylindrical glass jar is 20cm, and the jar is filled with salt water. A cone-shaped iron block is put into the jar and immersed in water. At this time, the paper rises by 1 / 20. It is known that the bottom radius of the cylindrical iron block is 10cm, and the height is 30cm

Happy Xiaoxiao,
10×10×3.14×30÷3÷（20×20×3.14）÷1/20
=3140÷1256÷1/20
=2.5÷1/20
=50 cm
A: the original water depth in the tank is 50 cm

In RT △ ABC, if the bisector of acute angle a intersects with the bisector of adjacent complementary angle of acute angle B at point D, then ∠ ADB =?
I'm not good at math. I hope you can give me some help. Please write down the steps. Thank you here

∠ADB=180°-∠CBD-∠CBA-∠DAB=180°-1/2(180°-∠CBA）－∠CBA-1/2∠CAB=180°-90°＋1/2∠CBA-∠CBA-1/2∠CAB=90°-1/2(∠CBA+∠CAB)=90°-1/2(180°-∠C）=1/2∠C