(1 1 / 2) + (- 5 / 6) + 2 3 / 4 - (minus 3 / 8) - (4 2 / 3) four One third times (2.71-0.31) times 2-1.1 three (negative one-third) - [- 1 + (1-02 times one and two-thirds) divided by (negative one-third) two 2） ] 2: Merge congeners 2a-[-3b+(4a-3a-b)] 2 2 2 9m+[4m -3n-(2m-6m)]

(1 1 / 2) + (- 5 / 6) + 2 3 / 4 - (minus 3 / 8) - (4 2 / 3) four One third times (2.71-0.31) times 2-1.1 three (negative one-third) - [- 1 + (1-02 times one and two-thirds) divided by (negative one-third) two 2） ] 2: Merge congeners 2a-[-3b+(4a-3a-b)] 2 2 2 9m+[4m -3n-(2m-6m)]

1,6/4+11/4+3/8+5/6-28/6
=17/4-23/6+3/8+34/8=37/8-23/6
=111/24-92/24
=19/24
0.33*(2.71-0.31)*2 －1.1
=0.33*2.4*2－1.1
=1.584-1.1
=0.484
-1/3-(-1+(1-0.33)/(-2))
=-1/3-(-1+0.67/(-2))
=-1/3-(-1-0.335)
=-1/3+1.335
=1.002
2a-[-3b+(4a-3a-b)]
=2a-(-3b+4a-3a-b)
=2a+3b-4a+3a+b
=a+4b
9m+[4m -3n-(2m-6m)]
=9m+(4m -3n-2m+6m)
=9m+4m -3n-2m+6m
=17m-3n

A 350 meter long train passes through a 1550 meter long tunnel. It takes two minutes from the front to the rear of the train to leave the tunnel. It takes two minutes to cross a 4400 meter long bridge at the same speed______ Minutes

(4400 + 350) / [(1550 + 350) / - 2] = 4750 / [1900 / - 2], = 4750 / - 950, = 5 (minutes). A: it takes 5 minutes

The circumference of a rectangle is 8 cm more than that of a circle. What is the area of the original circle
(the radius of a circle is the length of a rectangle)

Another one who can't ask questions
Let the radius of the circle be x, then the perimeter is 6.28x, then the perimeter of the rectangle is 6.28x + 8, then half of the perimeter of the rectangle is 3.14x + 4, then the width of the rectangle is 2.14x + 4
So the answer to this question is: you still can't ask questions!

Given sequence {an}, {BN} and function f (x), G (x), X ∈ r satisfy the following conditions:
b1=b,an=f(bn)=g(b(n+1))(n∈N*)
If f (x) = TX + 1 (t ≠ 0, t ≠ 2), G (x) = 2x, f (b) ≠ g (b), and lim (an) (n →∞) exists, find the value range of T and lim (an) (n →∞) (expressed by T)

From the condition: TBN + 1 = 2B (n + 1), and t ≠ 2, we can get B (n + 1) + 1 / (T-2) = (T / 2) [BN + 1 / (T-2)]. From F (b) ≠ g (b), t ≠ 2, t ≠ 0, we can know that B + 1 / (T-2) ≠ 0, t / 2 ≠ 0, so {BN + 1 / (T-2)} is an equal ratio sequence with the first term of B + 1 / (T-2) and the common ratio of T / 2. BN + 1 / (T-2) = [B + 1 / (T-2)] (T / 2) ^ (n -

The average taxi fare in Hangzhou is: the starting mileage is 4 km, and the starting fee is 10 yuan; if it exceeds the starting mileage, the taxi fare is still low
Keep the current 2 yuan / km unchanged. The distance from Wushan Square to east bus station is 10 km. How much more do you need to pay after the price adjustment?

10+(10-4)*2
=10+12
=22 yuan

The right figure ABCD is a right angled trapezoid. Take AB as the axis and rotate the trapezoid around this axis to get a rotating body. How many cubic centimeters is its volume?
AB 6cm BC 3cm CD 3cm
If you take CD as the axis and rotate the trapezoid around this axis, you can get a rotating body. What is its volume?

First of all, the figure is made up of two parts: a cone on the left, a circle on the bottom, a radius of 3cm and a height of ab-cd = 6-3 = 3cm; a cylinder on the right, a radius of 3cm and a height of 3cm. Therefore, v = (1 / 3) * (pi * 3 ^ 2) * 3 + (pi * 3 ^ 2) * 3 = 36pi

The ninth power of 9.99 × 10, the tenth power of 1.01 × 10, the ninth power of 9.9 × 10 and the tenth power of 1.1 × 10 are arranged in a row from small to large

9 × 10

How to do this math problem
Three barrels... Can hold 900... 300... 500 liters of water at most, 900 full. To put the 900's water, two of them should contain 100 liters... Can pour out the water... How to divide

First 900, then 500, then 300 (200)
500 to 900 (700 in 900)
900, 300, 300, 500 (400 in 900, 300 in 500)
900, 300, 300, 500
400-300=100 300+300-500=100
At this point 900 and 300 are both 100

As shown in the figure, the quadrilateral ABCD is a rectangle, the △ PBC and △ QCD are equilateral triangles, and the point P is above the rectangle, and the point q is inside the rectangle

It is proved that: (1) the ∵ quadrilateral ABCD is a rectangle. ∵ ABC = ∠ BCD = 90 ° (1 minute) ∵ the ∵ PBC and △ QCD are equilateral triangles. ∵ PBC = ∠ PCB = ∠ QCD = 60 ° (1 minute) ∵ PBA = ∠ ABC - ∠ PBC = 30 °, (1 minute) ∵ PCD = ∠ BCD - ∠ PCB = 30 °. ∵ PCQ = QCD - ∠ PCD = 30 °. ∵ PBA = ∠ PCQ = 30 ° (1 minute) (2) ∵ AB = DC = QC, ∵ PBA = PCQ, Pb = PC. (1 minute) ）≌△ PAB ≌△ PQC. (2 points) ≌ PA = PQ. (1 point)

We know that a multiplied by 2 / 7 = B multiplied by 7 / 5 = C multiplied by 7 / 7 and that a, B and C are not equal to 0. Please arrange a, B and C in the order from small to large