Given that the hyperbola x ^ 2-y ^ 2 / 4 = 1 of the line L intersecting through the fixed point P (0,1) lies at two points a and B, Q: if the midpoint of the line AB is m, find the trajectory equation of point M The answer is 4x ^ 2 - y ^ 2 + y = 0 (Y1)

Given that the hyperbola x ^ 2-y ^ 2 / 4 = 1 of the line L intersecting through the fixed point P (0,1) lies at two points a and B, Q: if the midpoint of the line AB is m, find the trajectory equation of point M The answer is 4x ^ 2 - y ^ 2 + y = 0 (Y1)

The straight line L passing through the fixed point P (0,1) is: y = KX + 1, which is substituted into hyperbola to get & nbsp; 4x & # 178; - (KX + 1) &# 178; = 4, which is sorted out to get & nbsp; (4-K & # 178;) X & # 178; & nbsp; - 2kx-5 = 0 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; (1) let a and B be divided into two parts

If X1 and X2 are two pieces of the quadratic equation 2x with the square of 5x-3 = 0, find the value of | x1-x2 | and find 1 / 2 of the square of X1 and 1 / 2 of the square of x2

2x²+5x-3=0
（2X-1)(X+3)=0
So we have X1 = 1 / 2, X2 = - 3 or X1 = - 3, X2 = 1 / 2
Then | x1-x2 | = 3.5
1/ x1²+1/ x2² =4+1/9=37/9

Let the edge length of a tetrahedron ABCD be a, p be any point on edge AB, and the distance from P to ACD, BCD be D1, D2, then D1 + D2 =?
Why do I make a d that is root 6 / 3 * a, two D should be multiplied by 2? Why is the answer just root 6 / 3 * a

You can take the special case that ABCD is a regular tetrahedron, and point P coincides with point A. D1 + D2 is the distance from point a to BCD. The answer is the root 6 / 3 * a

The square of (a + b) - 8 (a + b) + 16 / (a + b) - 16, where a + B = 5

[(a+b)^2-8(a+b)+16]/[(a+b)^2-16]
=[(a+b-4)^2]/[(a+b+4)(a+b-4)]
=(a+b-4)/(a+b+4)
=(5-4)/(5+4)
=1/9

If a polynomial plus 3x2y-3xy2 yields x3-3x2y, then the polynomial is
Don't copy it online,

One addend = and - another addend
According to the meaning of the title
(x³-3x²y)-(3x²y-3xy²)
=x³-3x²y-3x²y+3xy²
=x³-6x²y+3xy²

① A & # 178; + A + 1 / 4 ② (Y & # 178; - 6) & # 178; - 6 (Y & # 178; - 6) + 9 process!

A:
①a²+a+1/4
=a²+2*a*(1/2)+(1/2)²
=(a+1/2)²
②（y²-6）²-6（y²-6）+9
=(y²-6-3)²
=(y²-9)²
=(y-3)²(y+3)²

The area of the parallelogram is 20 square centimeters, and the lengths of the two adjacent sides are 4cm and 5cm respectively. What is the distance between the two groups of opposite sides?

The distance between two opposite sides is the height
Because the area of parallelogram = base × height
So height = area △ bottom = 20 △ 4 = 5cm
The other side is 20 △ 5 = 4cm high

4.7x minus x equals 85.1 to solve the equation

4.7x minus x equals 85.1
3.7x=85.1
3.7x÷3.7=85.1÷3.7
x=23

What is the tangent equation of curve y = 2x ^ 2 + 1 at point P (- 1,3)?
y'=4x
The tangent slope k = - 4 is obtained by substituting x = - 1
The tangent equation is Y-3 = - 4 (x + 1)
Why?
y'=4x
Why?
The tangent slope k = - 4 is obtained by substituting x = - 1

First of all, I have to ask you, have you studied derivative?
The geometric meaning of derivative is the slope of tangent passing through a point
According to the derivation rule, the process of obtaining the derivative of (2x & # 178; + 1) is as follows
(2x²+1)'
=(2x²)'+(1)'
=2(x²)'+0
=2×2x+0
=4x

7x-2.7 is equal to 0.3

7x-2.7=0.3
7x=2.7+0.3
7x=3
x=3÷7
X = 3 / 7 (3 / 7)