If the solutions of the linear equations 3x + y = 1 + A and X + 3Y = 3 satisfy x + y = 2, then the value of a is

If the solutions of the linear equations 3x + y = 1 + A and X + 3Y = 3 satisfy x + y = 2, then the value of a is

x+3y=3
x+y=2
y=0.5
x=1.5
3x+y=1+a
4.5+0.5=1+a
a=4

On the system of linear equations 3x + y = 1 + a x + 3Y = 3 of X, y to find the value of a

No solution
Is the title wrong

Discussion: the position relationship between circle C1: (x-1) 2 + (Y-3) 2 = R2 and circle C2: x2 + y2 = 16
In fact, I know the way of thinking, but I won't do it in terms of calculation. I hope I can have detailed calculation results

The radius given by circle C1 is unknown and needs to be discussed
The method is to calculate the distance between the centers of two circles, and then compare it with the sum of the two radii to get the position relationship

When calculating division, little careless mistakenly regards division 43 as 34, so the quotient is 32 and the remainder is 32. What is the correct quotient and the remainder?

32X34 = 1088 1088 + 32 = 1120 1120 divided by 43 = 26
The quotient is 26 and the remainder is 2

As shown in the figure, in △ ABC, e is a point on BC, EC = 2be, and point D is the midpoint of AC. suppose that the areas of △ ABC, △ ADF, and △ bef are s △ ABC, s △ ADF, and s △ bef respectively, and s △ ABC = 12, then s △ adf-s △ bef=______ ．

∵ point D is the midpoint of AC, ∵ ad = 12ac, ∵ s △ ABC = 12, ∵ s △ abd = 12S △ ABC = 12 × 12 = 6. ∵ EC = 2be, s △ ABC = 12, ∵ s △ Abe = 13s △ ABC = 13 × 12 = 4, ∵ s △ abd-s △ Abe = (s △ ADF + s △ ABF) - (s △ ABF + s △ BEF) = s △ adf-s △ bef

1 equals 5, 2 equals 10, 3 equals 15, 4 equals 20, 5 equals what?
just some fun

25

If P = | 1-2x | + | 1-3x | + | 1-4x | +... + | 1-10x |, for any allowable value of X in a certain range, the fixed value is ()

P = | 1-2x | + | 1-3x | + | 1-4x | +... + | 1-10x |,
That is, after summation, the final result of P does not contain x, that is, the coefficient of X is 0
So ± 2, ± 3, ± 4 The algebraic sum of ± 10 is 0
2 + 3 + 4 + 5 + 6 + 7 = 8 + 9 + 10
Therefore, when 1-7x ≥ 0, i.e. x ≤ 1 / 7,
P=[(1-2X)+(1-3X)+… (1-7X)]-[(1-8X)+...+(1-10X)]
=6-3=3.
When 1-7x1 / 7,
P=-[(1-2X)+(1-3X)+… (1-7X)]+[(1-8X)+...+(1-10X)]
=-6+3=-3.
In conclusion, the fixed value is ± 3

Use degree to express 37 ° 24 ′ 36 ″

37°24′36″
=37°24.6‘
=37°+24.6÷60°
=37°+0.41°
=37.41°

SiNx + cosx / SiNx cosx = 2, then sin (X-5 π) sin (3 π / 2-x) =?

(sinx+cosx)=2(sinx-cosx)
sinx=3cosx
And Sin & # 178; X + cos & # 178; X = 1
So cos & # 178; X = 1 / 10
sin(x-5π)sin(3π/2-x)=sin(x+π)(-cosx)
=sinxcosx
=3cos²x
=3/10

The ratio of solution 11 / 12 to X is equal to 1 / 4 to 6 / 7

22 out of 7