Given √ (x2 + 25) + √ (x2 + 7) = 36, find the value of √ (x2 + 25) - √ (x2 + 7)

Given √ (x2 + 25) + √ (x2 + 7) = 36, find the value of √ (x2 + 25) - √ (x2 + 7)

Given √ (x2 + 25) + √ (x2 + 7) = 36, find the value of √ (x2 + 25) - √ (x2 + 7) (√ (x2 + 25) - √ (x2 + 7)) (√ (x2 + 25) - √ (x2 + 7)) = x & # 178; + 25 - (X & # 178; + 7) = 18; √ (x2 + 25) - √ (x2 + 7) = 18 △ 36 = 1 / 2; I'm glad to answer for you, skyhunter 002 will answer for you if there is anything in this question

Given x + 1 / x = 9, find the value of X & # 178; + 1 / X & # 178

x+1/x=9
(x+1/x)²=81
x²+1/x²+2=81
x²+1/x²=79

Given X & # 178; = 9, | Y-1 | = 1, and x > y, find the value of X + y

X = 3, - 3 y = 2,0 because x is greater than y, there are two cases: x = 3, y = 2,x = 3, y = 0, so the value is 5 or 3

A rectangular pool is 4 meters long, 5 meters wide and 2 meters deep. The four walls and bottom of the pool should be plastered with cement. What is the area of plastering cement?

S = (4 + 5) x2x2 + 4x5 = 56 (M2)

4-2 1-6 5-12 11-20 19

4-1/2-5/6-11/12-19/20
=4-(1-1/2)-(1-1/6)-(1-1/12)-(1-1/20)
=4-1+1/2-1+1/6-1+1/12-1+1/20
=1/2+1/6+1/12+1/20
=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5
=1-1/5
=4/5

A rectangular steel plate is 18 decimeters long and 9 decimeters wide. Cut the largest circle from the top. How many square meters is the area of the remaining part?
Quick, urgent, please

The diameter of the largest circle is 9 decimeters
So the remaining area
＝18*9－π*(9/2)*(9/2)
＝162－81π/4
About 98.38 (square decimeter)

45 divided by 9 / 7 quotient less than 15, find the number, use the equation solution
A store sells a best-selling commodity. It sells 40% in the first day, and 10 pieces less in the second day than in the first day. There are 28 pieces left unsold. How many pieces of this commodity were there? （

Let this number be X
45÷9/7-X=15
35-X=15
X=35-15
X=20
This number is 20

The perimeter of the bottom surface of a cube fuel tank is 12 decimeters, and the area of the bottom of the tank is square decimeters. How many square decimeters of iron sheet should be used to make the fuel tank
Don't give me two answers

12 △ 4 = 3 decimeters (side length)
The tank bottom area is 3 × 3 = 9 square decimeters
Required iron sheet = 3 × 3 × 6 = 54 square decimeters
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The simple calculation of 3 / 8 + 4 / 7 + 1 / 4 × 2 / 5?

3/8+4/7+1/4×2/5
=3/8+4/7+1/10
=(3×35+160+28)/280
=293/280

In RT △ ABC, the bisector of acute angle a intersects with the bisector of the adjacent complementary angle of acute angle B at point D, then ∠ ADB=______ Degree

If the size of acute angle ∠ A is x, then the adjacent complementary angle of acute angle ∠ ABC is 90 ° + X; then ∠ ADB = 180 ° - (x2 + 90 ° - x + 45 ° + x2) = 45 °