The square of 3x minus 7x plus 2 is less than 0

The square of 3x minus 7x plus 2 is less than 0


Factorization
The square of 3x minus 7x plus 2



Read the following materials to solve the inequality (X-6) (x + 5) > 0. According to the "multiplication rule of rational numbers", that is, if two numbers are multiplied by each other, the same sign will get positive
X-6 > 0, x + 5 > 0 (1) or X-6 < 0, x + 5 > 0 (2), X is greater than 6 from 1, X < - 5, so x > 6, X < - 5, so x < - 5 from 2, so the solution set of inequality is x > 6 or X < - 5, please follow the solution above Lake to solve the inequality: x + 2 / 4x-5 > 0


(x + 2) / (4x-5) > 0
x+2>0 4x-5>0 ①
Or x + 25 / 4
So x > 5 / 4
X is obtained from 2



Solve inequality: (X-6) (x + 5) > 0. According to the "multiplication rule of rational numbers", that is, multiplication of two numbers with the same sign to get positive, we can get {X-6 > 0, x + 5 > 0 (1) or {x-6-5), so x > 6


Is this the solution of junior high school?
(x + 2) / (4x-5) > 0 is equivalent to (x + 2) (4x-5) / (4x-5) & # 178; > 0
Because (4x-5) &# 178; > 0 -------- it is both square and denominator
So we can get {x + 2 > 0, 4x-5 > 0 ① or x + 25 / 4, so x > 5 / 4
From 2 to X



How to decompose this factor: x ^ 3 + 3x ^ 2 + 5x + 3
Can you solve it in two ways?


Hello
x^3+3x^2+5x+3
=x^3+3x^2+2x+3x+3
=x(x²+3x+2)+3(x+1)
=x(x+2)(x+1)+3(x+1)
=(x²+2x+3)(x+1)
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Two barrels of oil a and B are 90kg in total. After pouring 1 / 6 of a barrel of oil into B barrel, the weight ratio of a and B barrels of oil is 4:5. How much is a and B


A: 90 × 4 / (4 + 5) / (1 / 6) = 48 kg
B: 90-48 = 42 kg



In the quadratic function y = x square + MX + N, where M-N = 0, then his image must pass through?
A.(1,1) B.(1,-1) C.(-1,1) D.(-1,-1)


C. (- 1,1) substituting x = - 1, y = 1 into y = x square + MX + N, we can get M-N = 0



60% of the boys in a class are equal to 9 / 10 of the girls. There are 30 boys. How many students are there in this class?


30% of boys are 30 × 60% = 18
The number of girls is 18 △ 9 / 10 = 20
So there are 30 + 20 = 50 students in the class



Given a & sup2; + B & sup2; + C & sup2; - AB BC CA = 0, a = 4, find the value of B and C


a²+b²+c²-ab-bc-ca
=1/2[(a-b)^2+(b-c)^2+(c-a)^2]=0
(a-b)^2+(b-c)^2+(c-a)^2=0
a-b=0
b-c=0
c-a=0
a=b=c=4



There are 42 more girls than boys in the fifth grade of a school, and 1 / 13 of girls is equal to 1 / 11 of boys


Suppose female X, male 1 / 13 △ 1 / 11x = 11 / 13X
x-11/13x=42
2/13x=42
x=42x13/2
x=273
Male 273x11 / 13 = 231
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In the equal ratio sequence {an}, it is known that A3 and A5 are the two roots of the quadratic equation x square + KX + 5 = 0, then the value of A2 × A4 × A6 is?


A3 = a1q ^ 2, A5 = a1q ^ 4, so A3 * A5 = (A1) ^ 2 · Q ^ 6 = (a1q ^ 3) ^ 2 = 5
So a1q ^ 3 = ± root 5
Then A2 × A4 × A6 = a1q × a1q ^ 3 × a1q ^ 5 = (A1) ^ 3 × Q ^ 9 = (A1 × Q ^ 3) ^ 3 = (± root 5) ^ 3
=The root number is 5