Factorization of 8 (a-b) ^ - 2 (B-A)

Factorization of 8 (a-b) ^ - 2 (B-A)

8(a-b)²-2(b-a)
=8(a-b)²+2(a-b)
=2(a-b)[4(a-b)+1]
=2(a-b)(4a-4b+1)

16 (a-b) ^ 2-9 (a + b) ^ 2 =? (factorization)

16(a－b)^2－9(a＋b)^2
＝[4(a－b)]^2－[3(a＋b)]^2
＝[4(a－b)＋3(a＋b)][4(a－b)－3(a＋b)]
＝(7a－b)(a－7b)．

dx/dt=y dy/dy=x x(0)=-1 y(0)=0
Find the equation of X, y with respect to t
How to get the answer can say the next process?

x=-（e^t+e^(-t))/2
y=-(e^t-e^(-t))/2
Because DX / dt = y, dy / dt = x, X (0) = - 1, y (0) = 0
So DX / dt = y and the derivative of t get d ^ 2x / dt ^ 2 = dy / dt = X
So d ^ 2x / dt ^ 2-x = 0, its characteristic roots are 1 and - 1
Using the characteristic equation, we get x = C1 * e ^ t + C2 * e ^ (- t)
So y = DX / dt = C1 * e ^ t-c2 * e ^ (- t)
Then x (0) = - 1, y (0) = 0 are taken into the solution of C1 and C2

The circumference of a rectangle is 26 cm. If the length of the rectangle is reduced by one cm and the width is increased by two cm, it will become a square. Let the length of the rectangle be x cm and the equation be?

The width is 26 △ 2-x = 13-x
x-1=13-x+2
x+x=15+1
2x=16
x=8
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There are six same cylindrical columns in the hall, each of which is 8 meters high, 2.4 meters in perimeter, and 4.5 square meters per kilogram of paint
M, how many kilos of paint do you need to paint these columns?

The upper and lower sides don't need to be painted, just the side of the column. Just calculate the side area
Side area = perimeter × height
2.4*6*8=115.2
115.2÷4.5=25.6kg

Calculator m +, M -, MRC, GT, CE, no / AC, Mu what is the use? For example!
For example! Some of the answers are very vague! Read other people's answers and did not read the same!

MRC: press this key for the first time to call the contents of memory, and clear the contents of memory for the second time. GT: press GT key to transfer the contents of GT storage register to the display register; press AC or

How to find the (x + 2) - power differential of E?
Please give a detailed answer

Je ^ (x + 2) DX = JE ^ (x + 2) d (x + 2) = JDE ^ (x + 2) = e ^ (x + 2) (J is the integral sign)

It is known that a, B are opposite numbers to each other, C, D are negative reciprocal numbers to each other, and the absolute value of X is equal to twice of its opposite number. Find XXX + abcdx + a -- BCD

a. B is opposite to each other: a + B = 0
c. D is reciprocal: CD = - 1
The absolute value of X is equal to twice of its opposite number: | x | = - 2x, = = = = > x = 0
xxx+abcdx+a--bcd=0+abcd*0+a-b(-1)=a+b=0

How to add, subtract, multiply and divide 4.5.6.7 to get 24

1:4 × (5 - 6 + 7)2:4 × ((5 - 6) + 7)3:4 × (5 - (6 - 7))4:4 × (5 + 7 - 6)5:4 × ((5 + 7) - 6)6:4 × (5 + (7 - 6))7:4 × (7 + 5 - 6)8:4 × ((7 + 5) - 6)9:4 × (7 + (5 - 6))10:4 × (7 - 6 + 5)11:4 ×...

Y = | X-1 | + | 3x + 2 | in the form of piecewise function

When x ＜ - 2 / 3, y = 1-x-3x-2 = - 4x-1;
-When 2 / 3 ≤ x ≤ 1, y = 1-x + 3x + 2 = 2x + 3;
When x > 1, y = X-1 + 3x + 2 = 4x + 1;
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