If the factorization result of the polynomial ax squared + BX + C is (4x + 3) (4x-3), then a = --- B = --- C is equal to

If the factorization result of the polynomial ax squared + BX + C is (4x + 3) (4x-3), then a = --- B = --- C is equal to

（4x+3）（4x-3）=16x^2-9
a=16
b=0
c=-9

The numerator of indefinite integral is DX, and the denominator is x square minus 2,

∫dx/（x²-2）=√2/4ln|（x-√2）/（x+√2）|+C

∫ indefinite integral of 2x ^ 4 + 2x ^ 2 + 1 / x ^ 2 + 1dx! The numerator is 2x ^ 4 + 2x ^ 2 + 1, the denominator is x ^ 2 + 1, followed by a DX!

∫ (2x & # 8308; + 2x & # 178; + 1) / (X & # 178; + 1) DX = ∫ [2x & # 178; (X & # 178; + 1) + 1] / (X & # 178; + 1) DX, which splits the molecule into two terms = ∫ [2x & # 178; + 1 / (X & # 178; + 1)] DX = 2 · X & # 179 / / 3 + arctan (x) + C = (2 / 3) x & # 179; + arc

Three vertices of triangle ABC are on circle O, D and E are arc AB, arc AC midpoint, chord de intersect AB at point F and AC at point G respectively

It is proved that connecting ad, AE, CE ∵ e is the middle point of arc AC ∵ arc AE = arc CE ∵ EAC corresponds to arc CE ∵ ECA corresponds to arc AE ∵ EAC = ∵ ECA ∵ ade, ∵ ECA corresponds to arc AE ∵ ade = ∵ ECA ∵ ade = ∵ EAC ∵ D is the middle point of arc AB ∵ arc ad = arc BD ∵ bad corresponds to arc B ∵

When he calculates division, he writes the divisor 43 as 34, so that the quotient is 32 and the remainder is 32. What is the correct quotient and the remainder

Quotient: 1120. Remainder: 2
Formula: quotient multiplier divisor plus remainder equals divisor

As shown in the figure, in △ ABC, ad is the bisector of ∠ BAC, and the straight line EF ⊥ ad intersects with the extension lines of AB, AC and BC at points e, F and K, respectively. It is proved that: ∠ k = 12 (∠ ACB - ∠ b)

It is proved that ∵ ad bisects ∵ BAC, ∵ bad = ∵ DAC = 12 ∵ BAC, ∵ EF ⊥ ad, ∵ DOK = 90 °, ∵ k = 90 ° - ∵ ADK = 90 ° - (∵ B + ∵ ABC2), 12 ∵ BAC = 90 ° - 12 (∵ B + ∵ ACB), ∵ k = 90 ° - ∵ b-90 ° + 12 ∵ ACB = 12 (? ACB - ? b)

A number divided by a, quotient 5 and 2, this number is?

5a+2

X (I:

Take all elements of line I of X matrix
The use of ":" in MATLAB is very flexible, simply speaking, it represents the whole row or column elements in the matrix

Divide the following numbers into prime factors 18 32 45 51 75 84, 24 and 36 into prime factors, and point out which of them have the same prime factors

18=2×3×3
32=2×2×2×2×2
45=3×3×5
51=3×17
75=3×5×5
84=2×2×3×7
24=2×2×2×3
36=2×2×3×3
The same prime factors are 2 and 3

How can y = (1 / 2) sin (2x + π / 6) + 1 be obtained by y = SiNx (x ∈ R) transformation?

This is easy:
Moving up one unit, the amplitude becomes 1 / 2 of the original, then moving to the left π / 12, the period reduces to 1 / 2 of the original
That is y = (1 / 2) sin (2x + π / 6) + 1