The equation kx2 - (k-1) x + 1 = 0 of X has rational roots, so we can find the value of integer K

The equation kx2 - (k-1) x + 1 = 0 of X has rational roots, so we can find the value of integer K

(1) When k = 0, x = - 1, the equation has rational roots. (2) when k ≠ 0, because the equation has rational roots, if K is an integer, then △ = (k-1) 2-4k = k2-6k + 1 must be a complete square, that is, there is a non negative integer m, such that k2-6k + 1 = m2

Given that the sum of X + 2 / A and X-2 / B is equal to X & sup2; - 4 / 4x, then what is a equal to and what is B equal to

[A / (x + 2)] + [B / (X-2)] = 4x / (X & sup2; - 4) through the partition, we get [a (X-2) + B (x + 2)] / (X & sup2; - 4) = 4x / (X & sup2; - 4) [(a + b) x + 2b-2a] / (X & sup2; - 4) = 4x / (X & sup2; - 4) (a + b) x + 2b-2a = 4x, the coefficient is a + B = 42b-2a = 0, the solution is a = b = 2

Find the value of X. the square of 3 (X-5) - 75 = 0

3（x-5）²=75
（x-5）²=75÷3
（x-5）²=25
X-5 = 5 or - 5
So: x = 10, or x = 0

0.75 + (- 11 / 4) + 0.125 + (- 5 / 7) + (- 4 and 1 / 8) = write the steps and the simplest algorithm
0.75 + (- 11 / 4) + 0.125 + (- 89 / 7) + (- 4 and 1 / 8)=

0.75 + (- 11 / 4) + 0.125 + (- 89 / 7) + (- 4 and 1 / 8)
=3/4-11/4+1/8-89/7-4-1/8
=(3/4-11/4)+(1/8-/18)-4-89/7
=-2+0-4-12-5/7
=-18 and 5 / 7

An ammeter g with resistance Rg = 50 Ω and full bias current Ig = 1mA is to be refitted into a voltmeter with measuring range u = 3V,
An ammeter G has resistance Rg = 50 Ω and full bias current Ig = 1mA. To refit it into a voltmeter with measuring range of u = 3V, what is the resistance in series? What is the internal resistance of the refitted voltmeter?

① UG = Ig times RG = 0.05v u string = 3-0.05v = 2.95v r string = u string Ig = 2950 Ω
② R inner = RG + R string = 3000 Ω
It seems so

3 of 8 * 1 of 7 + 3 of 8 * 5 of 7

3/8 * 1/7 + 3/8 * 5/7
= 3/8 * (1/7 + 5/7)
= 3/8 * 6/7
= 3/4 * 3/7
= 9/28

There is a symbol in mathematics similar to the English letter U. how to read this symbol?

Are you talking about it
μ
Miu

A wonderful composition of life because of love, more than 200 words,

It seems that you don't like writing articles. Let me give you the next one. Life is wonderful because of love. In our life, maybe you don't pay attention to it, maybe you don't feel it, maybe you don't understand it, and can't understand it. However, we are full of love everywhere. Love is everywhere, love is everywhere, love is full of the world. Maybe

Can a transformer with a rated capacity of 100 KVA carry a load of 100 kW? Why?

When the power factor is 1, 100kVA and 100kW are equal, but when the power factor is 0.9, 100kW is equivalent to 111kva, but more than 10% of the load transformer can still bear, but the operation time is limited, can't run for a long time, if the power factor is lower, then the transformer can't bear

It is known that the area of a rectangle is 3a2-3b2. If the length of one side is a + B, then its perimeter is a______ ．

(3a2-3b2) / (a + b) = 3 (a + b) (a-b) / (a + b) = 3a-3b. The perimeter can be obtained as: 2 [(a + b) + (3a-3b)] = (8a-4b). Therefore, (8a-4b) should be filled in