Given that the hyperbola passes through P (3,4), his asymptote equation is 2x + y = 0. Find the standard equation of hyperbola and its half focal length Is there mdian on the hyperbola whose distance product from the two asymptotes equals or exceeds the half focal length of the hyperbola? If so, ask for the coordinates of M. if not, explain the reason

Given that the hyperbola passes through P (3,4), his asymptote equation is 2x + y = 0. Find the standard equation of hyperbola and its half focal length Is there mdian on the hyperbola whose distance product from the two asymptotes equals or exceeds the half focal length of the hyperbola? If so, ask for the coordinates of M. if not, explain the reason

Let the hyperbola be: x ^ 2 / A ^ 2-y ^ 2 / b ^ 2 = 1 and over narrow (3,4), B / a = 2. The standard equation is: x ^ 2 / 5-y ^ 2 / 20 = 1, half focal length = C = 5, let m (x0, Y0) D1 = | 2x0 + Y0 | / root 5, D2 = | 2x0-y0 | / root 5d1 * D2 = | 4x0 ^ 2-y0 ^ 2 | / 5 | 4x0 ^ 2-y0 ^ 2 | > 25

How to do the seventh question on page 15 of PHS in the first semester of sixth grade?

In quadratic function, how to judge a + B + C > 0?

Because the analytic expression of quadratic function is y = ax ^ 2 + BX + C, when the value of X is 1, y is equal to a + B + C, and then you look at the image. When the value of X is 1, is the corresponding value of Y on the positive half axis or negative half axis of Y. if it is on the positive half axis, that is, y is greater than 0, it is a + B + C > 0. If it is on the negative half axis, that is, y is less than 0, it is a + B + C < 0
We must draw and analyze, and cultivate the thought of combination of number and shape

The child has a math problem: "there are 20 1s. Please add the sign of addition, subtraction, multiplication and division or brackets between them to make the formula equal to 2005."
I really can't answer,

Easy!
[(11111-1111)÷(11-1)X(1+1)+1+1+1+1+1]X1=2005

If sin (x + y) / sin (X-Y) = m / N, then the value of tany / TaNx is?
It is helpful for the responder to give an accurate answer

Sin (x + y) / sin (X-Y) = m / N (sinxcosy + cosxsiny) / (sinxcosy cosxsiny) = m / N divided by sinxcosy (1 + tany / TaNx) / (1-tany / TaNx) = m / NN (1 + tany / TaNx) = m (1-tany / TaNx) (m + n) tany / TaNx = m-tanny / TaNx = (m-n) / (M + n)

Add appropriate operation symbol or bracket to make equal sign 4.24.24.24.24.24.24.2 = 0
4.2 4.2 4.2 4.2 4.2 =1
4.2 4.2 4.2 4.2 4.2 =2

(4.2-4.2)*4.2*4.2*4.2=0
(4.2-4.2)*4.2+4.2/4.2=1
(4.2*4.2/4.2+4.2)/4.2=2

If the function f (x) = Tan ω x (ω > 0) and the length of the line is π / 4, then the value of F (π / 4) is

It can be seen from the drawing that the length between Tan values is its period, so the period of the function is π / 4
π/│ω│=π/4（ω＞0）
∴ω=4
∴ f(x)=tan 4x
X = π / 4: F (π / 4) = Tan π = 0

Ask the fourth grade of primary school math answers, do not use equations to solve problems
Car a and car B start from city a and city B at the same time and travel opposite each other to the destination city C. car a travels 110 kilometers per hour, car B travels 120 kilometers per hour, car B repairs for one hour, and the two cars arrive at City C at the same time. How many kilometers are there between city a and city B

Because car B drives more than car a (120-110 = 10) kilometers per hour, car a drives one hour more than car B, so time = car a's speed (car a's speed - car a's speed) = 11 hours, so the distance between the two cities = 11 × 110 + (11-1) × 120 = 2410 kilometers
Why did everyone else miscalculate? I don't believe you can use the equation to check. You didn't consider the distance b drove after repairing the car

Known: straight line y = 2x + m ellipse 4x ^ 2 + y ^ 2 = 1 ask: when m what value, l and C have different intersection
1. Find: when m is the value, l and C have different intersection points
2. When m = 5 + root 17, find the nearest distance between L and C
Process! Thank you!

Nearest distance = 10

The answer to the secret volume of unit 2 of Chinese final sprint 100 in Grade 5 of primary school

This kind of thing is done by yourself! Don't always rely on others! Do your own questions! Who will help you write them in the exam? You need to do it yourself