78 * 27 + 21 * 27 + 27 simple calculation

78 * 27 + 21 * 27 + 27 simple calculation

78*27+21*27+27
=(78+21+1)x27
=100x27
=2700
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Solution equation: 2 (X-2) - 3 (4x-1) = 9 (1-x)

Remove brackets: 2x-4-12x + 3 = 9-9x, shift: 2x-12x + 9x = 9 + 4-3, merge similar terms: - x = 10, coefficient 1: x = - 10

(- 81) ÷ 2 1 / 4 + 4 / 9 (- 16)

(- 81) ÷ 2 1 / 4 + 4 / 9 (- 16)
=-81×4/9+4/9×（-1/16）
=-36-1/36
=-36 and 1 / 36

0.5x-3 / 0.04-x = 0.4 (0.5x-3) / 0.5 deformation, removing denominator, removing bracket, shifting term, merging coefficient of similar term into 1

0.5x-3/0.04-x=0.4(0.5x-3)/0.5
deformation
50x-300/4-x=(2x-12)/5
De denominator
5(50x-300)-20x=4(2x-12)
Remove brackets
250x-1200-20x=8x-48
transposition
250x-20x-8x=-48+1200
Merge congeners
222x=1152
The coefficient is reduced to 1
x=192/37

1 / 2 + 1 / 4 + 1 / 8 + 1 / 16 + 1 / 32 + 1 / 64 + 1 / 128 is equal to? Why? Simple calculation

127 / 128 because the denominator after each item is the first half, you can add 1 / 128 at the end of the original formula. You can find that from the back to the front, two 1 / 128 add up to 1 / 64, then two 1 / 64 add up to 1 / 32, and so on,... Finally, two 1 / 2 add up to 1

Elective course 4-1: plane geometry as shown in the figure AB is the diameter of ⊙ o, the extension line of chord BD and Ca intersects at point E, and the extension line of EF perpendicular to Ba intersects at point F. (I) verification: ∠ DEA = ∠ DFA; (II) if ∠ EBA = 30 °, EF = 3, EA = 2Ac, find the length of AF

(I) prove: connect ad, BC, because AB is the diameter of ⊙ o, so ∠ ADB = ∠ ACB = ∠ EFA = 90 °, so four points a, D, e, f are in common circle, and ∩ DEA = ∠ DFA; (II) in right angle △ EFA and right angle △ BCA, so ∩ EFA ∽ BCA, so AFAC = aEAb, so AF × AB = AC ×

When calculating the division, little careless wrongly wrote the divisor 43 as 34, so the quotient is 32 and the remainder is 30

32*34=1088 1088+30=1118
1118/43=25.33

In △ ABC, ad is the bisector of ∠ a, de and DF are perpendicular to AB and AC respectively, and the perpendicular feet are e and F, BD = DC, be = CF

So DF = De
It is also RT △ BD = DC, so HL DCF congruent DEB  be = CF

If a is divided by B, the quotient is 5, and the remainder is 2. If a and B are expanded 10 times at the same time, the quotient is 5______ , Yu______ ．

Suppose a = 17, B = 3, then the formula can be written as: 17 △ 3 = 5 2. Expand a and B 10 times to 170 △ 30 = 5 20. So the answer is: 5, 20

Function zeros (1,8) in MATLAB

Zeros (1,8) is to create a zero matrix with one row and eight columns. Attached: usage of zeros B = zeros (n) returns an n-by-n matrix of zeros.An error message appears if n is not a scalar.B = zeros(m,n) or B = zeros([m n]) returns an m-by-n ma...