The square of X + the square of Y + 2x + 2Y = 1

The square of X + the square of Y + 2x + 2Y = 1

So, let x + y = m, then y = M-X, change the original equation into the equation form of circle: (x + 1) ^ 2 + (y + 1) ^ 2 = 3, and then you make the plane coordinate axis, then the equation y = M-X is a straight line with slope of - 1 and longitudinal intercept of M. the straight line has two tangent lines with the circle. Find out the position of the two tangent lines, get the equation, and finally get the value of M, which is the answer
I calculated it as - root 6-root 2 to root 6-root 2

f(x)=1/(sinx)^2+2/(cosx)^2 （0(tanx)^4=2--->tanx=+'-2^(1/4)
So there is a minimum value of 3 + 2 √ 2
I didn't learn Secant and cosecant

1 / (cosx) ^ 2 + 2 / (SiNx) ^ 2 = [1 / (cosx) ^ 2 + 2 / (SiNx) ^ 2] * [(SiNx) ^ 2 + (cosx) ^ 2] (anyway (SiNx) ^ 2 + (cosx) ^ 2 = 1, it's OK to multiply) = (SiNx / cosx) ^ 2 + 1 + 2 + 2 (CoS / SiNx) ^ 2 the first term and the last term can be solved by means inequality > = 3 + 2 √ 2

It is known that the intersection of the line y = 2x + 1 and y = 3x + B is in the third quadrant. Two values of constant B are written out by calculation

X=1-B
Y=3-2B
The intersection is in the third quadrant, X

If f (2x + 1) = 3x-2 and f (a) = 4, then a =?

3x-2=4
x=2
a=2x+1
=2*2+1
=5

Make a 256 cuboid carton without cover. If the bottom of the carton is a cube, how much is the height of the carton
minimum

The title is incomplete

Given that the function f (x) = AX2 + 2x is odd, then the real number a=______ ．

If f (- x) = - f (x) is defined as an odd function, then f (- 1) = A-2 = - f (1) = - (a + 2), the solution is a = 0

It is known that a and B are opposite to each other, C and D are reciprocal to each other, and the absolute value of X is 5
The absolute value of X - (a + B + CD) + (a + b) + (3-cd)

AB is opposite to each other, so a + B = 0
CD is reciprocal, CD = 1
x-（a+b+cd）+\（a+b）-4\+\3-cd\
=X-(0+1)+\0-4\+\3-1\
=X-1+4+2
=X-5
The value is 0 or - 10
When x = 5, the value is 0
When x = - 5, the value is - 10

Given the function f (log takes 2 as the base and X as the real number) = X-1 / x, find the analytic formula of the function,

Let log take 2 as the base, X as the true number = t, then x = the t power of 2, so f (T) = the t power of 2 - 1 / (the t power of 2)
So f (x) = x power of 2-1 / (x power of 2)

AB is two nonzero vectors, the angle is α, when a + TB is the minimum
(1) Finding the value of T
(2) When AB is collinear, it is proved that B is perpendicular to a + TB

This is a one-dimensional quadratic equation about t, the opening upward, obviously the minimum value taken at the symmetry axis, that is, the minimum value of T = - 2, the minimum value taken at the symmetry axis, that is, the minimum value of T = - 2, that is, the minimum value of T = - 2, that is, the minimum value of T = - 2, that is, the minimum value of T = - 2, that is, t = - 2, the minimum value of the minimum value of the minimum value of the minimum value of the minimum value of T = - 2, that is the minimum value of T = - 2, that is the minimum value of T = - 2, that is the minimum value of the minimum value of 2.a, the minimum value of the minimum value of 2.a, the minimum value of the minimum value of the minimum value of the minimum value of 2.a, the minimum value of the minimum value of the minimum value of the minimum value of the minimum value of the minimum value of the minimum value of the minimum value of the minimum value of the minimum value of the minimum value of the minimum B collinear b * (a + TB) = a * B + T | B | ^ 2 not

What is the domain of the function f (x) = LG (1 / x + 3)?

The domain of definition is: {x | x > - 3}