Ohm's law does not mean that when the voltage is constant, the current is inversely proportional to the resistance Ohm's law doesn't mean that when the voltage is constant, the current is inversely proportional to the resistance. But if the resistance of the common series circuit is different, the current is the same

Ohm's law does not mean that when the voltage is constant, the current is inversely proportional to the resistance Ohm's law doesn't mean that when the voltage is constant, the current is inversely proportional to the resistance. But if the resistance of the common series circuit is different, the current is the same


I don't know which level you are asking this question. If you are in college physics, you have to consider factors such as phase
If it's a physics problem in junior high school or senior high school, such as DC circuit, I'll give you a brief summary to see if it can be solved
The current of the same circuit is equal - the same circuit refers to a closed circuit, including power supply, electrical appliances and other devices. Before solving such problems, you must first find the same or fixed parameters, so that you can proceed to the next step and make no mistake
Your problem is that you don't distinguish the preconditions. You should first use the theory of "series voltage division", that is, in a series circuit, the voltage of each electrical appliance is different, so you don't apply Ohm's law, because the premise of Ohm's law is that when the voltage is constant, in your question, Ohm's law is applicable to each individual consumer in series, because when it comes to a specific individual consumer, the voltage is fixed. Similarly, if several consumers in the circuit are connected in parallel and then connected in series with others, the voltage of these consumers in parallel is the same, and Ohm's law can also be applied
In physics, whether it's electricity or mechanics, we must remember the definition of laws or physical terms, otherwise it's easy to get into mistakes



How to solve these factorization problems
1.(c^2-b^2+d^2+a^2)-4(ab-cd)^2
2.x^3(a+1)-xy(x-y)(a-b)+y^3(b+1)
3.m^4+m^2-2mn-n^2+1
4.(ab+cd)(a^2-b^2+c^2-d^2)+(ac+bd)(a^2+b^2+c^2+d^2)
(Note: the number after the ^ sign represents the number of letters,


1. The original formula = (1 + 2b) * (1-2b) a ^ 2 + 8bcd * a + C ^ 2 + D ^ 2-4c ^ 2D ^ 2-B ^ 2 the last term cannot be decomposed, while the first and last term cannot form 8bcda, so it can be determined that the problem cannot be decomposed
2. The original formula = x ^ 3 (a + 1) - XY (X-Y) (a-b) + y ^ 3 (B + 1)
=ax^3+x^3-ayx^2+byx^2+axy^2-bxy^2+by^3+y^3
=ax(x^2-xy+y^2)+by(x^2-xy+y^2)+(x+y)(x^2-xy+y^2)
=〔(a+1)x+(b+1)y〕(x^2-xy+y^2)
=(ax+x+by+y)(x^2-xy+y^2)
3. The original formula = (m ^ 4 + 2m ^ 2 + 1) - (m ^ 2 + 2Mn + n ^ 2)
=(m^2+1)^2-(m+n)^2
=(m^2+1+m+n)(m^2+1-m-n)
4. The title is wrong, and the last bracket should be - C ^ 2-D ^ 2
Original formula = (AB + CD) (a ^ 2-B ^ 2 + C ^ 2-D ^ 2) + (AC + BD) (a ^ 2 + B ^ 2-C ^ 2-D ^ 2)
=(a^2-d^2)(ab+cd+ac+bd)+(c^2-b^2)(ab+cd-ac-bd)
=(a-d)(a+d)(a+d)(b+c)+(c-b)(c+b)(a-d)(b-c)
=(a-d)((b+c)[(a+d)^2-(b-c)^2]
=(a-d)(b+c)(a+d+b-c)(a+d-b+c).
Otherwise, you cannot merge the same category later
If LZ is still more difficult to decompose, try to decompose the question "6x ^ 4 + 18mx ^ 3-6x ^ 3-6x ^ 3-6x ^ 3-6x ^ 3 + 30x ^ 2x ^ 2x ^ 2x ^ 2x ^ 2x ^ 2x ^ 2x ^ 2x ^ 6x ^ 2x is also more difficult to decompose, try to decompose the question" 6x ^ 4 + 18mx ^ 4 + 18mx ^ 3-6x ^ 3-6x ^ 3-6x ^ 3-6x ^ 3 + 30x ^ 2x ^ 2x ^ 2x ^ 2x ^ 2x ^ 3 + 18mx ^ 18mx ^ 18mx ^ 18mx ^ 18mx ^ 18mx ^ 18mx ^ 18mx ^ 18mx ^ 18mx ^ 18mx ^ 18mx ^ 3 ^ 18mx ^ 18mx ^ 18mx ^ 3-2x ^ 3-3-3-3-3-3-3-3-3-3-3~ 2Z-
10myz^2-10yz^3+20m^2yz-18my^2x+6xy^3-30y^3z+36y^4-6my^3+6my^2z+6y^2z^2-12y^2m^2+10x^2zp+30zpmx-10zpyx
+50yz^2p-60y^2zp-2zpmy-10z^2pm-10z^3p-12x^2zp-36mypx+12y^2px-60y^2pz+72y^3p-12my^2p+12ypmz+12ypz^2-24m^2yp-6p^2x^2-18mxp^2+6xyp^2-30yzp^2+36p^2y^2-6myp^2+6p^2mz+6p^2z^2-12P^2m^2+24x^2z^2+72mz^2x-24yz^2+120yz^3-144y^2z^2+24myz^2-24mz^3+24z^4+48m^2z^2
The answer is = (2x + 3Y + 4Z + 3P) (3x-2y + 6z-2p) (x + 2y-z + m) (x-3y + Z + 2m)



How many days are there from March 21, 2010 to December 13, 2012?


There are 999 days from March 21, 2010 to December 13, 2012 (including March 21, 2010 and December 13, 2012)
365 * 3 + 1 - (31 + 28 + 20) - (31-13) = 1096-79-18 = 999 (days)



Write the algorithm to get the maximum value of any three integers a, B, C
Solution: the first step: use Max to represent the maximum, and assume that max = a
Step 2: compare the size of Max and B, if Max


At the beginning, Max is a. first compare the size of a and B. If AB, then Max will still be a, because Max always represents the largest number. After a round of comparison, Max will be represented as the larger number, so that after all comparisons, Max will be larger than all other numbers, that is, the largest number



The Shanghai World Expo will be held from May 1 to October 31, 2012. May 1 is a Saturday and October 31 is a day of the week


31 + 30 + 31 + 31 + 30 + 31 = 184 184-1 = 183 183 divided by 7 = 26 The day after Saturday is Sunday, so the answer is Sunday



(x+a)(x+b)=?


X square + (a + b) * x + A * B



There are some interesting symmetries in the operation of numbers, such as 12x231 = 132x21____ X462=_____ X_____


12*462=264*21



It takes 24 days for Party A to do a job alone, and 16 days for Party B to do it alone. Now this job is done by Party A for one day, and then Party A and Party B cooperate. In the middle, Party A takes another day off. When they work again, the work efficiency of Party A and Party B increases by 20%. They work for another three days to complete the task, and ask Party A to have a rest on the next day


Take the whole work as 1. If a does it alone for 24 days, then he does 1 / 24 a day. Similarly, if B does 1 / 16 a day, if a has a rest on day x, then a works (x-1) days before the rest, while B does not rest but works one day late. Therefore, both of them work (x-1) days before improving efficiency. After improving efficiency, a does 120% × 1 / 2 a day



Simple calculation of 25 × 44


25X4X11
=100X11
=1100



How many times do 50 students shake hands to greet each other?


49+48+47+...+3+2+1=50*24+25=1225