What's 32 times two fifths In fact, I just want to test your computing ability. On the other hand, I want to help "novice" @ XX answer the most comprehensively.

What's 32 times two fifths In fact, I just want to test your computing ability. On the other hand, I want to help "novice" @ XX answer the most comprehensively.

32×2/5=12.8

It's 32
The same two numbers

2*2*2*2*2=32
4 √ 2 * 4 √ 2 = 32 (root)

What's 32 times 4.5

144

Ellipse x square + y square = 1 the value range of real number m with focus on Y axis

The topic is not complete
Use the following conclusion. Satisfy the following conditions
(1) The coefficients in front of X and y are positive,
(2) If the focus is on the y-axis, then the coefficient in front of X & # 178; is greater than that in front of Y & # 178

Find the minimum value of (SiNx cosx + 1) / x from 0 to 180 degrees

A:
The minimum value of F (x) = (SiNx cosx + 1) / X in (0, π]
Derivation:
f'(x)=(cosx+sinx)/x-(sinx-cosx+1)/x^2
=(xcosx+xsinx-sinx+cosx-1)/x^2
Let g (x) = xcosx + xsinx SiNx + cosx-1
Derivation:
g'(x)=cosx-xsinx+sinx+xcosx-cosx-sinx
=(cosx-sinx)x
When 0

It is known that the intersection points of the straight lines y = 2x + 1 and y = 3x + B are in the third quadrant

According to the meaning of the question, we get y = 2x + 1y = 3x + B, the solution is x = 1 − by = 3 − 2B, so the intersection coordinates of y = 2x + 1 and y = 3x + B are (1-B, 3-2b), ∫ the intersection is in the third quadrant, ∫ 1 − B < 03 − 2B < 0, the solution is b > 32, that is, the value range of B is b > 32

If the function f (x) = 2ax2-x-1 has exactly one zero point in (0,1), then the value range of a is ()
A. （1，+∞）B. （-∞，-1）C. （-1，1）D. [0，1）

When △ = 0, a = - 18, there is a zero point x = - 2, which is not on (0, 1), so it does not hold. The function f (x) = 2ax2-x-1 has exactly a zero point in (0, 1), that is, f (0) f (1) < 0, that is - 1 × (2a-1) < 0. The solution is a > 1, so a is selected

A cube box can just hold a cylinder with a volume of 628 cubic centimeters. What's the volume of this box?

Let the edge length of a cube be x cm
（x÷2)×(x÷2)×3.14×x=628
(x×x)÷4×x =200
x×x×x =800
So the volume of cube is 800 cubic centimeter

The range of y = X-2 ax on [1,3]

Y=X^2-2aX=(X-a)2-a^2,
Axis of symmetry: x = a,
When A3, the range is [9-6a, 1-2a]

Let a be the difference between the opposite number of - 3 and the absolute value of - 11, and B be a number 3 larger than - 5, and find the value of a-b

a=3-|-11|= - 8
b=-5+3=-2
a- =-8-(-2)=-6