Given the product of (x's square + ax) (2x's square-b), the coefficient of the square of X is - 6, and the coefficient of the cube of X is - 5

Given the product of (x's square + ax) (2x's square-b), the coefficient of the square of X is - 6, and the coefficient of the cube of X is - 5

If your question is (x ^ 2 + ax) (2x ^ 2-B), remove the brackets to get 2x ^ 4 + 2aX ^ 3-bx ^ 2-abx, then - B = - 6,2a = - 5, a = - 2.5, B = 6. If your question is (x ^ 2 + ax) [(2x) ^ 2-B], remove the brackets to get 4x ^ 4 + 4ax ^ 3-bx ^ 2-abx, then - B = - 6,4a = - 5, a = - 1.25, B = 6

How to simplify the multiplication of the square of X-2 by the square of x 2

Just square it

In a trapezoid with an upper bottom of 5cm, a lower bottom of 8cm and a height of 6cm, cut the largest parallelogram. The area of the cut parallelogram is []
The area of the remaining part is [] cm2
What's the area of the rest

5*6=30

A multiplied by five sixths equals B multiplied by three fifths equals C multiplied by four fifths equals D multiplied by three eighths. What are a, B, C and D respectively (a
BCD is not 0)

The question is not clear. Do you want this answer?
a=72、b=40、c=75、d=160

Given that the tangent equation of the image of function f (x) at point m (1, f (1)) is 2x-3y + 1 = 0, then f (1) + F '(1)=______ ．

From the tangent equation 2x-3y + 1 = 0, we get the slope k = 23, that is, f ′ (1) = 23, and the tangent point is on the tangent equation, so substituting x = 1 into the tangent equation, we get 2-3y + 1 = 0, and the solution y = 1, that is, f (1) = 1, then f (1) + F ′ (1) = 23 + 1 = 53

The solution of 3 (x-4) = 6-2 (1-x)
It's a system of inequalities

3(x-4)

Find the function y = sin2x + acosx + 5 / 8A + 3 / 2, the maximum value of the closed interval 0 to the half pie

The maximum value of the function y = sin2x + acosx + 5 / 8a-3 / 2 on the closed interval [0, half pie]?
=sinx^2+acosx+5/8a-3/2
=1-cosx^2+acosx+5/8a-3/2
=-(cosx-a/2)^2+5/8a+a^2/4-1/2
If cosx = A / 2, there is obviously a maximum value of a ^ 2 / 4 + 5 / 8a-1 / 2 (a ∈ [0,1])
Let a ^ 2 / 4 + 5 / 8a-1 / 2 = 1
The solution is a = - 4 (rounding off) or a = 2 / 3
If a / 2 > 1, it is obvious that the maximum value is obtained when cosx = 1
Then the original function can be resolved as: a + 5 / 8a-3 / 2 = 1, a = 20 / 13 > 1
If a / 20 is in contradiction with the condition, it should be discarded
Therefore, when a = 2 / 3 or 20 / 13, the maximum value of this function is 1

The difference between a number and its reciprocal is 9 and 9 in 10. What's the number?

The denominator is 10
So the reciprocal of this number is obviously one in 10
So the number is 10

It takes 1.3 parts of x plus 1 = y 2 (x + 1) - 6 = 62.2x-y = 6 x + 2Y = - 2 to solve binary linear equation

I can't understand the title. Can you take a picture of the title? I'll give you two yuan each time

Let f (x) = x Λ n + X-1 (n ≥ 2, n ∈ n *), then the number of zeros of F (x) in the interval (1 / 2,1) is

f(1/2)=(1/2)^n+1/2-1=(1/2)^n-1/2
f(1)=1^n+1-1=1
And because n > = 2, f (1 / 2) = (1 / 2) ^ n-1 / 2 must be less than 0
F (1 / 2) 0, so f (x) has at least one zero point in (1 / 2,1)
Let's look at monotonality
The derivative of F (x) is NX ^ (n-1) + 1, which must be greater than 0 when n > = 2
So f (x) increases monotonically on (1 / 2,1), and f (1 / 2) 0
So there's only one zero
Choose B