When m is an integer, one-third x minus one times m equals one minus two-thirds M It needs a very detailed process and explanation. You'd better answer it tonight and use it tomorrow

When m is an integer, one-third x minus one times m equals one minus two-thirds M It needs a very detailed process and explanation. You'd better answer it tonight and use it tomorrow

Is m (x-1) / 3 = 1-2m / 3?
Transfer merger:
m(x-1+2)/3=1
m(x+1)/3=1
x+1=3/m
x=-1+3/m
If x is not conditional, M is not zero
If x is an integer, M = - 3, - 1,1,3

How much is negative two minus 24 multiplied by brackets 1 / 3 minus 1 / 2 plus 1 / 4?

13 out of 6

Let A1 = 5, a (n + 1) = √ (4 + an), find the limit of the sequence,

Take the limit on both sides of the equation, and mark the limit as a, then we can get the equation, where a square minus a shear 4 equals 0, then we can solve it

Simplification: ① (3a-1) (2a + 1) ② (m-3n) (M + 7n) ③ (2x-5y) (2y-3x)

（1）（3a-1）（2a+1）
=6a²+(3a-2a)-1
=6a²+a-1
（2）（m-3n）（m+7n）
=m²+(7n-3n)m+7n×(-3n)
=m²+4mn-21n²
（3）（2x-5y)(2y-3x)
=4xy-6x²-10y²+15xy
=-6x²+19xy-10y²
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Function f (x) = (1 + x-x22 + x33-x44 + -The number of zeros of cos2x on interval [- 3, 3] is ()
A. 3B. 4C. 5D. 6

Let g (x) = 1 + x-x22 + x33-x44 + -Then G ′ (x) = 1-x + x2-x3 + +X2012 = 1 + x20131 + X, in the interval [- 3, 3], 1 + x20131 + X ＞ 0, so the function g (x) is an increasing function in [- 3, 3], because the exponent of X on the right side of G (- 3) is negative before even degree term

Given the function y = (K + 3) x ^ (2k-1), when k takes what value, it is an inverse proportional function

Inverse scale function is defined as y = k x ^ (- 1)
So the problem is very simple, 2k-1 = - 1, k = 0

Decimal root with writing, such as 1.5 times root 2,

I haven't written like this. I'm used to writing scores! If it's purely numerical calculation, it's better not to write like this!

Use the substitution elimination method to solve this equation. My friends will do it quickly and send it quickly. Although the reward is only 5, I hope you can help me

5X+6Y=16,(1)
2X-3Y=1 (2)
(1) + (2) times 3
We get 11x = 19, x = 19 / 11
Substituting x = 19 / 11 into (2) yields y = 9 / 11

3.5x-14.5 = 3.5-x to solve the equation, check the calculation (don't skip steps!)

3.5x-14.5=3.5-x
transposition
3.5x+x=3.5+14.5
4.5x=18
x=4
Substitute x = 4 into the equation
Left = 3.5 * 4-14.5 = - 0.5
Right = 3.5-4 = - 0.5
So x = 4 is the root of the equation

It is known that the left vertex of the ellipse is a, and two perpendicular chords am and an intersect the ellipse at two points m and N through A. (1) when the slope of the line am is 1, calculate the coordinates of point m; (2) when the slope of the line am changes, whether the line Mn passes a certain point on the x-axis. If it passes a fixed point, please give a proof and find the fixed point. If it fails, please explain the reason

(1) When the slope of the straight line am is 1, the straight line am: y = x + 2, (1 point) is substituted into the elliptic equation and simplified to be: 5x2 + 16x + 12 = 0, (2 points) the solution is X1 = - 2, X2 = - 65, ｜ M (- 65, 45); (4 points) (2) let the slope of the straight line am be K, then am: y = K (x + 2), then y = K (x + 2) x24 + y2 = 1, and the simplification is as follows: