Use the appropriate method to solve the equations 2010x + 2011y = 20102011x + 2010Y = 2011

Use the appropriate method to solve the equations 2010x + 2011y = 20102011x + 2010Y = 2011


2010x + 2011y = 2010 is formula ①, 2011x + 2010Y = 2011 is formula ②, using formula ① - ②
=2010x + 2011y-2011x-2010y = 2010-2011 Y-X = - 1 y = X-1 y = X-1 y = X-1 is obtained by taking y = X-1 into formula (1)
201ox + 2011 (x-1) = 2010 201ox + 2011x-2011 = 2011 4021 x = 4021 x = 1 when x = 1
The above formula y = X-1 = 1-1 = 0



Given a = 2010x + 2010Y, B = 2011x + 2011y, C = 2012x + 2012y, then (a-b) 2 - (B-C) 2=______ .


The original formula = (a-b + B-C) (a-b-b + C), = (A-C) (a-2b + C), ∵ a = 2010x + 2010Y, B = 2011x + 2011y, C = 2012x + 2012y, ∵ the original formula = (2010x + 2010y-2012x-2012y) (2010x + 2010y-4022x-4022y + 2012x + 2012y) = (- 2x-2y) (4022x + 4022y-4022x -



The matching motor of a water pump has a rated power of 2200W, a coil resistance of 3 ohm and a working current of 10A at the voltage of 220V
How much heat is generated by the coil in 1s? How much electricity is consumed in 1s? How high can the water be pumped in 30 minutes?


The heat generated by the coil in 1s is q = I & # 178; RT = 10 * 22 = 220j
Electric energy consumed in 1s e = Pt = 2200j



If 4m + | m | = 3M is known, then the value range of M is______ .


∵ 4m + | m | = 3M, ∵ m | = - m, ∵ m ≤ 0



If an electric kettle is marked with the word "220V 880W", then it can work normally for 30min. What is the power consumption? Rated power
What is the rated current? What is the resistance during normal operation?


W=Pt=880×30×60=1584000J
I=P/U=880/220=4A
R=U/I=220/4=55Ω



First simplify, then evaluate: [(X-Y) &# 178; + (X-Y) (X-Y)] 2x, where x = 3, y = 1.5


[(x-y)²+(x-y)(x-y)]÷2x
=2[(x-y)²]÷2x
=[(x-y)²]÷x
=【3-1.5】²÷3
=1.5²÷3
=2.25÷3
=0.75



A certain electrical appliance is marked with 220 V 40 W. when the electrical appliance works normally, what is the current passing through it and its resistance?
I use p = UI, I = 0.18a, r = 1222 Ω
But if we use p = u ^ 2 / R to calculate R, it is equal to 1210 ohm. If we use p = I ^ 2 R to calculate R, it is even more wrong
Why?


The current shall be:
I=P/U=40/220I≈0.1818(A)
Resistance:
R=U/I=220/0.1818≈1210(Ω)
R=U×U/P=220×220/40=1210(Ω)
R=P/(I×I)=40/(0.1818×0.1818)≈1210(Ω)



As shown in the figure is a plane schematic diagram of a machine part with rectangular outline. According to the dimensions in the figure (unit: mm), the distance between the centers of two circular holes a and B is calculated as______ mm.


∵AC=150-60=90mm,BC=180-60=120mm,∴AB=AC2+BC2=1202+902=150mm.



What does the line of action mean in physics?


Force can be represented by a line segment with an arrow. The line segment is drawn according to a certain proportion (scale). Its length indicates the size of the force, its direction indicates the direction of the force, and the arrow or the tail of the arrow indicates the action point of the force. The straight line along the square line of the force is called the action line! This method of representing force is called the diagram of force~



How many parts of 9 equals three parts of 1 equals three parts of 27?


Nine out of twenty-seven equals one-third and twenty-seven out of eighty-one