The curve y = x - 1 / 2 square, the tangent equation at point (1,1) is

The curve y = x - 1 / 2 square, the tangent equation at point (1,1) is

Is it y = x ^ (- 1 / 2) \
y'=(-1/2)*x^(-3/2)
Tangent slope of curve at point (1,1)
k=y'|(x=1)=-1/2
The tangent equation of a curve at point (1,1) is
y-1=-1/2(x-1)
That is, x + 2y-3 = 0

The tangent equation of the square + 1 of the curve y = x at point (1,2) is as follows:

Y = x & sup2; + 1, the coordinates of point (1,2) are substituted to satisfy the curve equation,
So points (1,2) are points on the curve,
Y & acute; = 2x, substituting the point (1,2) coordinates into Y & acute; = 2x = 2 * 1 = 2,
So the tangent slope of the curve at point (1,2) is 2,
So the tangent equation is: Y-2 = 2 * (x-1)
That is, y = 2x

Given the function f (x) = LG (x + √ (x2 + 1)) + cosx, and f (- 2010 = a), then f (2010)=

F (x) = LG [x + radical (x ^ 2 + 1)] + cosx (1) your topic is a little unclear. I'll do it according to this first. I'm not talking about it
F (- x) = LG [- x + radical (x ^ 2 + 1)] + cos (- x) = LG [- x + radical (x ^ 2 + 1)] + cosx. ② cosx is even function
①+②
F (x) + F (- x) = LG [x + radical (x ^ 2 + 1)] + LG [- x + radical (x ^ 2 + 1)] + 2cosx
F (x) + F (- x) = LG {[x + radical (x ^ 2 + 1)] * [- x + radical (x ^ 2 + 1)]} + 2cosx = LG [- x ^ 2 + x ^ 2 + 1] + 2cosx
f(x)+f(-x)=lg1+2cosx=2cosx
f(2010)+f(-2010)=2cos2010
f(-2010)=a
f(2010)=2cos2010-a

Among the numbers 18, 29, 35, 41, 58, 70 and 87, the prime number has (), which is both composite and odd

Prime numbers are: 29, 41,
It's both composite and odd: 35, 87
Students such questions can ask the students around ah, make clear the definition of composite number and prime number, clear distinction, I wish you good results

Let the probability density of two-dimensional random variables (x, y) be f (x, y) = KX (X-Y), 0

1=∫(0~2)∫(-x~x) kx(x-y)dydx
1=∫(0~2) kx(xy-y^2/2)|(-x~x) dx
1=∫(0~2)2kx^3dx
1=2kx^4/4(0~2)
1=8k
k=1/8
You can see the scope by drawing
fy(y)=∫(|y|~2) kx(x-y)dx
=kx^3/3-kyx^2/2 | |y|~2
=1/8(8/3-2-(y^2|y|/3-y^3/2))
=1/12-y^2|y|/24+y^3/16
(-2

Given the quadratic function FX = AX2 BX + C, if F1 = 0, judge the number of zeros of the function for any f2-x = F2 + X

Because f (2-x) = f (2 + x)
So f (x) is symmetric with respect to x = 2,
So B / 2A = 2

The greatest common factor and the least common multiple of 12 and 6

The common factor is 6 and the common multiple is 12

If a2-2a = 1, then 2a2-4a=______ Based on______ ．

∵ a2-2a = 1, both sides are multiplied by 2 to get: ∵ 2a2-4a = 2, so the answer is: 2, the property of the equation is 2

How to make an example of a triangle rotating into a cone in the Geometer's Sketchpad?

To turn a cone, you can only turn a right triangle,
To do this, you have to learn how to draw ellipses. There are many ways to draw ellipses. Let me give you the simplest example

The solution of linear inequality of one variable by X-2 of 5 ≥ 3 + 2 of 2

Remove the denominator and get 2x ≥ 30 + 5x-20
If the items of the same kind are merged, we can get - 3x ≥ 10
If the coefficient is reduced to one, X ≤ 10 / 3