Points P1 (x1, Y1), P2 (X2, Y2). If p1p2 = | x2-x1 |, then the positions of P1 and P2 are Such as the title

Points P1 (x1, Y1), P2 (X2, Y2). If p1p2 = | x2-x1 |, then the positions of P1 and P2 are Such as the title

P1P2=|x2-x1|,
Note: Y1 = Y2, that is: p1p2 parallel to the X axis

It is known that P1 (x1, Y1) is a point on the line L: F (x, y) = 0, P2 (X2, Y2) is a point outside the line L. the positional relationship between the line and the line L represented by the equation f (x, y) + F (x1, Y1) + F (X2, Y2) = 0 is ()
A. Overlap each other B. parallel to each other C. perpendicular to each other D. oblique to each other

∵ P1 (x1, Y1) is a point on the straight line L: F (x, y) = 0, ∵ f (x1, Y1) = 0. ∵ P2 (X2, Y2) is a point outside the straight line L, ∵ f (X2, Y2) ≠ 0. The straight line represented by the equation f (x, y) + F (x1, Y1) + F (X2, Y2) = 0 is the parallel of F (x, y) + F (X2, Y2) = 0 and the straight line L

What's 88 degrees 48 minutes 36 seconds

88 degrees 48 minutes 36 seconds is 88.81 degrees

Five people shake hands with each other once, a total of three times______ Times

5 × 4 / 2, = 20 / 2, = 10 (Times); answer: a total of 10 times

153°19′41〃+20°43′48〃=?
RT

174°3′29〃

When the solution of the equation AX-2 = - x is a natural number, the value of integer a is

ax-2=-x
（a+1）x=2
The solution of X is a natural number only when a = 0 or a = 1

A simple calculation of 9.16 × 1.53-0.05 × 9.160.279 × 343 + 0.657 × 279 is necessary
Simple calculation
9.16×1.53-0.05×9.16
0.279×343＋0.657×279

9.16×（1.53-0.05）

Sina + cosa = M = √ 2Sin (a + π / 4)

Sina + cosa = radical 2 (radical 2 / 2sina + radical 2 / 2cosa) = radical 2 (COS π / 4sina + sin π / 4cosa) = radical 2Sin (a + π / 4)
After the use of the trigonometric function of the sum of the two corners of the trigonometric function of the formula

2006 × 2008-2 / 2006 + 2008 × 2005 how to calculate?

2006 × 2008-2 / 2006 + 2008 × 2005
=2008*（2006+2005）-1003
=2008*4011-1003
=8054088-1003
=8053085

As shown in the figure, ⊙ P and ⊙ o intersect at two points a and B, ⊙ P passes through the center O, and point C is any point of AB on the superior arc of ⊙ P (not coincident with points a and b), connecting AB, AC, BC and OC. (1) point out an angle equal to ∠ ACO in the figure; (2) when point C is at what position on ⊙ P, is the straight line CA tangent to ⊙ o? Please explain the reason; (3) when ∠ ACB = 60 °, what is the size relationship between the radius of two circles? Please state your reasons

(1) In ⊙ o, ⊙ OA = ob, ⊙ OA = ob, ⊙ ACO = ⊙ BCO; (2) connect OP and extend the intersection with ⊙ P at point D. if point C is at point D, the straight line CA is tangent to ⊙ O. reason: connect AD and OA, then ⊙ Dao = 90 °, OA ⊥ Da ⊙ Da is tangent to ⊙ o, that is, when point C is at point D, the straight line CA is tangent to ⊙ O. (3) when ⊙ ACB = 60 °, the radii of two circles are equal Make the diameter OD, connect BD, ad, OA, ∵ ∠ ADB = ∠ ACB = 60 ° Po, divide AB, Ao = Bo, ∵ ∠ ADO = ∠ BDO, ∵ ADO = 30 °, ∵ od is the diameter, ∵ Dao = 90 °, ∵ OA = 12od, ∵ OA = Po, when ∠ ACB = 60 ° the radii of the two circles are equal