The perimeter of a circular flower garden is 50.24 meters, in which there are four kinds of flowers (tulips, peonies account for 1 / 3, lilies and roses account for 6 / 1). How many of them each? Brother and sister

The perimeter of a circular flower garden is 50.24 meters, in which there are four kinds of flowers (tulips, peonies account for 1 / 3, lilies and roses account for 6 / 1). How many of them each? Brother and sister


Radius of flower bed = 50.24 △ 2 △ 3.14 = 8M
The area of flower bed = 3.14 × 8 × 8 = 200.96 square meters
Area of planting tulip = area of planting peony = 200.96 × 1 / 3 ≈ 66.99 square meters
Area of planting Lily = area of planting rose = 200.96 × 1 / 6 ≈ 33.49 square meters



The perimeter of a circular flower garden is 50.24 meters. Four kinds of flowers are planted in it. Among them, the area of tulip accounts for 35%. How many square meters is the area of tulip? The number is the integer


According to the theme, the radius of a circular flower bed is 50.24 divided by 3.14, and then divided by 2, equal to 8 meters
So the total area of the garden is 3.14 times 8 square meters, which is 200.96 square meters,
So the area of tulip is 200.96 times 35%, which is equal to 70.336 square meters, which is about 70 square meters,
So the area of tulip is 70 square meters



The perimeter of a circular flower bed is 37.68 meters. Four kinds of flowers of the same area are planted in the flower bed. How many square meters is the planting area of each kind of flowers


The radius is: 37.68 △ 3.14 △ 2 = 6m
The area of flower bed is: 3.14 × 6 × 178; = 113.04 square meters
The area of each flower is: 113.04 △ 4 = 28.26 square meters
If you don't understand, please ask



A brief calculation of 2008-2009


=2007 + 1-2009 / 2008
=2007 + 2009 1 / 2
=2007 and 2009



In the cube abcd-a1b1c1d1, O1 is the center of a1b1c1d1, e and F are the midpoint of AB and BC respectively. The tangent value of the angle between AO1 and EF is obtained


Make the center O of the surface ABCD, connect AC, oo1, ∵ EF ∥ AC ∥ AO1 and EF, and the angle is = ∠ oao1, ∵ abcd-a1b1c1d1 is the cube, so a1b1c1d1 is the vertical projection of the surface ABCD, ∵ oo1 ⊥ surface ABCD, oo1 ⊥ Ao, oo1 = Aa1, let the side length of the cube abcd-a1b1c1d1 be 1, then Ao = √ 2 / 2, oo1 = 1, Tan ∥ OAO



How to solve the square of x-7x + 10 = 0?
(x-2)(x-5)=0
How to do cross multiplication in this step? I went to bed in class


Cross multiplication
1 -2
1 -5
x²-7x+10=0
(x-2)(x-5)=0
x-2=0 x-5=0
X = 2 or x = 5
therefore
x1=2,
x2=5



Given the set a = {a, a + D, a + 2D}, B = {a, AQ, AQ ^ 2}, where D ≠ Q, a = B, find the value of D and Q


Because a + D ≠ a + 2D, D ≠ 0 is the same as Q ≠ 1, a ≠ 0
And because a = B
So ① a + D = AQ, a + 2D = AQ ^ 2
So a = 2aq-aq ^ 2
So Q ^ 2-2q + 1 = 0
Q = 1 (shed)
②a+d=aq^2 a+2d=aq
So 2aq ^ 2-aq-a = 0
So 2q ^ 2-q-1 = 0
Q = 1 or 0.75
So d = 0.25, q = 0.75



Guess the idiom according to the formula: 7-3-4 () 4 △ 5 () 10-9 = 1 ()


1. Lose everything
2. Fall apart
3. Lack of food and clothing



The height of a parallelogram is 1.8cm, and the height of the other parallelogram is 1.5cm
D: My pictures


S=h1*h2/(sina)
We also need to know the inner angle of the parallelogram



It is known that the circumference of a semicircle is 51.4cm. What is the radius of the semicircle?


51.4÷(3.14+2)
=51.4÷5.14
=10 cm