Calculate (x + y) ^ 2 + 10 (Y-X) + 25

Calculate (x + y) ^ 2 + 10 (Y-X) + 25

=x^2+y^2+10y―10x+2xy+25

The factor is divided into 16-8 (X-Y) + (X-Y) 2 =___ ．

16-8 (X-Y) + (X-Y) 2, = [4 - (X-Y)] 2, = (4-x + y) 2

If a line with slope 2 passes through three points a (3, 5), B (a, 7), C (- 1, b), then a=______ ．b=______ ．

A straight line with a slope of 2 passes through three points a (3,5), B (a, 7), C (- 1, b), ｜ 7 − 5A − 3 = B − 5 − 1 − 3 = 2, ｜ a = 4, B = - 3, so the answer is 4-3

There are 336 people in the two fire brigades, five out of seven in team a and three out of seven in team B. a total of 188 people are taken out to put out the fire. How many people are there in each fire brigade?
Formula or equation is the best formula

Set up a team of X people
5X/7+3/7(336-X)=188
5X/7+144-3X/7=188
2X/7=44
X=154
Team a = 154
Team B = 336-154 = 182

Today is Sunday, November 21. In 14 days, what day is it?

It's very simple, every week 7 days is the same day, so 14 days later is Sunday;
According to the number of months, November has 30 days, so 10 days after the 21st is December 1st, and 4 days after the 21st is December 5th
So the answer is Sunday, December 5th

A. The distance between B and a is 450 km. A and B start from a and B at the same time and run in opposite directions. It is known that the speed of a is 120 km / h and that of B is 80 km / h. After t hours, the distance between two vehicles is 50 km, then the value of T is ()
A. 2 or 2.5B. 2 or 10C. 10 or 12.5d. 2 or 12.5

(1) When car a and car B do not meet, according to the meaning of the question, we get 120t + 80t = 450-50, and the solution is t = 2; (2) when the two cars meet and the distance between them is 50km, according to the meaning of the question, we get 120t + 80t = 450 + 50, and the solution is t = 2.5

If a: C = 3:5 and C = 20, then B=

If a: C = 3:5 and C = 20, then the square of a = 12 and B = 400-144 = 256 (Pythagorean theorem), that is, B = 16

When car a runs five eighths of the whole journey, car B runs two fifths of the whole journey. At this time, the distance between car a and car B is 95 km,
When car a arrives at station B, how many kilometers is car B away from station B?
(answer with arithmetic)

Whole course: 95 ÷ (5 / 8-2 / 5) = 3800 / 9
In the whole process of line a, line B: 2 / 5 △ 5 / 8 = 16 / 25
Distance from station B: 3800 / 9 × (1-16 / 25) = 152km

Given that a, B and C are three sides of △ ABC, and A2 + B2 + C2 = AB + AC + BC, then △ ABC is ()
A. Isosceles triangle B. right triangle C. equilateral triangle D. isosceles right triangle

The original formula can be reduced to 2A2 + 2B2 + 2c2 = 2Ab + 2Ac + 2BC, that is, A2 + B2 + C2 + A2 + B2 + c2-2ab-2ac-2bc = 0; according to the complete square formula, we can get: (a-b) 2 + (C-A) 2 + (B-C) 2 = 0; from the properties of non negative numbers, we can know that A-B = 0, C-A = 0, B-C = 0; that is, a = b = C. so △ ABC is an equilateral triangle, so we choose C

The speed of an off-road vehicle is 20% faster than that of a motorcycle, and the speed of a motorcycle is several percent slower than that of an off-road vehicle

About 17%. This can only be about in percentage. It's easy to faint,