Given that XY satisfies that one fourth of x equals one fifth of Y, what is the ratio of X to y

Given that XY satisfies that one fourth of x equals one fifth of Y, what is the ratio of X to y

Positive proportion

We know that the square of X, the square of y plus the square of x plus four, XY plus thirteen are equal to six, the value of X, XY

∵x²y²+x²+4xy+13=6x
∴（xy+2）²+（x-3）²=0
∴（xy+2）>=0
（X-3）>=0
∴xy+2=0
x-3=0
∴xy=-2,x=3
∴xy=3×y=-2,y=-2/3
∴x=3,y=-2/3

If x + y = 6, xy = 2, then x ^ 2 + y ^ 2-xy=

It's 30
x^2+y^2-xy=(x+y)~2-3xy
(x+y)~2=x~2+2xy=y~2=36
-3xy=-6
x^2+y^2-xy=36-6=30

Find the function. Y = 4x square + 24 + 35 image symmetry axis, vertex coordinates and X axis intersection coordinates

Y = 4x ^ 2 + 24x + 35. = 4 (x + 3) ^ 2-1 axis of symmetry x = - 3 vertex (- 3, - 1) y = 4x ^ 2 + 24x + 35 = (2x-7) (2x-5) coordinates of intersection of X axis (7 / 2,0) (5 / 2,0)

The greatest common factor of two natural numbers is 12, and the least common multiple is 108. What are the two numbers?

12 and 36. The greatest common factor is 12, which means that one of the numbers is the least 12, and the least common multiple is 108 / 12 = 9. The other number is the combination of 12 and 9, which is 36

Given that a > 0, b > 0, and a + B = 2, the minimum value of AB + (2 / AB) is?

A:
a>0,b>0
a+b=2>=2√(ab)
0

Let y = f (x) have n derivatives in a neighborhood of x = 0, and f (0) = f '(0) = =f^(n-1)(0)=0
Using Cauchy mean value theorem to prove f (x) / x ^ n = f ^ (n) (θ x) / N!, 0 〈θ 〈 1

As long as 2, 8, 1, 12, 13, 14, 15, 16, 21, 24, 30, 34, 36, 38, 39... Are included in the supplementary questions
40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50. I don't want all of them, just these pages

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28.5 is 3.5 less than four fifths of a number. What's the quotient of dividing one fifth of 120 by the sum of two thirds and two fifths?
Expression

28.5 is 3.5 less than four fifths of a number
x*4/5-28.5=3.5
x*4/5=32
x=160÷4
x=40
What is the quotient of one fifth of 120 divided by the sum of two thirds and two fifths?
120*1/5÷(2/3+2/5)
=40÷2*(1/3+1/5)
=20÷8/15
=20×15/8
=37.5

The solving process of {10 + 2x ≤ 11 + 3x, 7 + 2x > 6 + 3x}

10+2x≤11+3x;
3x-2x≥10-11
x≥-1;
7+2x＞6+3x;
3x-2x＜7-6;
x＜1;
∴-1≤x＜1
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