The quotient of the reciprocal of 25 divided by 52 is______ ．

The quotient of the reciprocal of 25 divided by 52 is______ ．

The reciprocal of 25 is 52, 52 △ 52 = 52 × 25 = 1, so the quotient of the reciprocal of 25 divided by 52 is 1, so the answer is: 1

It is known that the polynomials AX2 + 2bxy + x2-x-2xy + y about X and y do not contain quadratic terms, so we can find the value of 5a-8b

∵ the polynomials AX2 + 2bxy + x2-x-2xy + y of X and y do not contain quadratic terms, ∵ a + 1 = 0, 2b-2 = 0, so a = - 1, B = 1, then 5a-8b = - 5-8 = - 13

Why? Li Bai walked on the street with nothing to do. He picked up the pot and went to buy wine. When he met the shop, he doubled it. When he saw the flower, he drank a bucket. When he met the shop and the flower three times, he drank all the wine in the pot. How much wine was in the pot
Why do you do this?
The original x Doujiu
2(2(2x-1)-1)-1=0
2(4x-2-1)-1=0
8x-4-2-1=0
8x=7
x=0.875
The original 0.875 Doujiu
Isn't that ok?
(1+1+1)/2/2/2=0.375
Original 0.375 Doujiu

Since it is not explained how to meet the restaurant and the garden, the following discussion is divided into two parts. Let's set the original wine in the pot as X. if we meet a restaurant multiplied by 2, we will reduce one when we meet the garden
1. If you meet three restaurants first and then three gardens, then x * 2 * 2-1-1 = 0, then x = 3 / 8
2. If you meet the second garden first and then the third restaurant, then (X-1-1) * 2 * 2 * 2-1 = 0, then x = 17 / 8
3. If you meet the garden first, then the restaurant, then the garden, then the restaurant 2, then the garden, then [(x-1) * 2-1] * 2 * 2-1 = 0, then x = 13 / 8
4. 2 [2 (2x-1) - 1] - 1 = 0
The solution is x = 0.875

If M and N are opposite numbers, and M is not equal to 0, then it must be true
Please select one: n / M is greater than 0
n/m=1
n/m=-1
n/m=o

n/m=-1

Calculate minus five sixths minus three eighties plus minus two and seven eighties

Minus five sixths minus three eighties plus minus two and seven eighties
=-(23/8+3/8)-5/6
=-13/4-5/6
=-39/12-10/12
=-49/12
=-4 and 1 / 12

It is known that the solution of the equation KX = 4-x about X is a positive integer

The original equation is transformed into KX + x = 4, that is, (K + 1) x = 4, the solution of the equation KX = 4-x about X is a positive integer, and the product of K + 1 and X is 4, then K + 1 = 4 or K + 1 = 2 or K + 1 = 1 can be obtained, and the solution is k = 3 or K = 1 or K = 0. Therefore, the integer solution of K can be obtained as 0, 1, 3

Calculation: 4.8 times (5 / 6 plus 5 / 8 minus 5 / 12) 4 / 15 minus 0.64 plus 13 / 5 minus 0.36

4.8x（5/6+5/8-5/12)
=4.8x5/6+4.8x5/8-4.8x5/12
=4+3-2
=5
4/15-0.64+13/5-0.36
=(4/15+13/5)-(0.64+0.36)
=(4/15+39/15)-1
=43/15-1
=28/15

It is proved that X & # 179 / / y + Y & # 179 / / X ≥ 1 / 2 (x + y) &# 178;, x > 0, Y > 0
Why not divide up and down by an X or y at the same time
Become x square / (Y / x) + y square / (x / y) ≥ (x + y) square / (Y / x + X / y) Cauchy inequality
Then we use the binomial mean inequality Y / x + X / Y ≥ 2

You don't know the proportion relation. 2 of denominator is the maximum value, which corresponds to the minimum value of the fraction. Prove that inequality can't be enlarged or reduced arbitrarily!

Point can make 1,2,3,4,5,6,7,8 equal to 100?

1+(2-3+4+5+6)*7-8+9=100
1+2-3+4+5*(6+7+8)-9=100
(1+2-3+4+5)*(6+7)-8-9=100
1+2-3+(4+5)*(6+7)-8-9=100
1+2-(3+4-5-6-7)*8+9=100
1+(2-3+4*5+(6-7)*8)*9=100
1+(((2-3+4)*5+6)/7+8)*9=100
1+(2-(3+4)*(5-6)/7+8)*9=100
1+(2-(3+4)*5)*(6+(7-8)*9)=100
1+(2-3+4*(5*(6-7)+8))*9=100
1+(2-3+4)*5*6-(7-8)*9=100
1+(2-3+4*(5/(6-7)+8))*9=100
(1+(2-3+4*5)/6)*(7+8+9)=100
1+(2-(3+4)/(5-6)/7+8)*9=100
1+2-3+4/5*(6+7*(8+9))=100
(1+2-3+4)/5*(6+7*(8+9))=100
(1+2-3+4/5)*(6+7*(8+9))=100
1+2-3-4+5+6*(7+8)+9=100

Factorization: 2Y ^ 2-2xy + 2x ^ 2-ay-ax-a ^ 2

Original formula = (X-Y) ^ 2 + x ^ 2 + y ^ 2-A ^ 2-ay-ax
=(x+y-a)^2-(a^2-ax-ay)-a^2
=(x+y-a)^2+a(x+y-a)-a^2
=[1/2 *(x+y-a)-a]*[2*(x+y-a)+2a]
=(x+y) *(x+y-3a)