Calculate [1] (- A ^ 2) ^ 2x (- 2A ^ 3) ^ 2 [2] (- 2 / 3A ^ 2B ^ 3C) ^ 3x (9 / 2Ab) Calculate [1] (- A ^ 2) ^ 2x (- 2A ^ 3) ^ 2 【2】(-2/3a^2b^3c)^3x(9/2ab^2)^2

Calculate [1] (- A ^ 2) ^ 2x (- 2A ^ 3) ^ 2 [2] (- 2 / 3A ^ 2B ^ 3C) ^ 3x (9 / 2Ab) Calculate [1] (- A ^ 2) ^ 2x (- 2A ^ 3) ^ 2 【2】(-2/3a^2b^3c)^3x(9/2ab^2)^2

【1】(-a^2)^2x(-2a^3)^2
=a^4x4a^6
=4a^10
【2】(-2/3a^2b^3c)^3x(9/2ab^2)^2
=-4/9a^6b^9c^3x 81/4 a^2b^4
=-9a^8b^13c^3
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The intersection point of y = SiNx and y = cosx in [0, Π / 2] is p. at point P, the area of the triangle bounded by the tangent of two functions and X axis is

In [0, π / 2], SiNx and cosx intersect at (π / 4, √ 2 / 2)
(sinx)'|=cos(π/4)=√2/2
(cosx)'|=-sin(π/4)=-√2/2
This is a symmetrical isosceles triangle. Considering the height of the vertex, the bottom edge is divided into two equal segments, m in length
If √ 2 / M = k = √ 2 / 2, then M = 2 and the length of the bottom edge is 4
S=√2*4/2=2√2

A right triangle, it has an angle of 45 degrees, the hypotenuse of the triangle is 10 cm long, then the area of the triangle is______ Square centimeter

Square area: 10 × 10 = 100 (cm2) triangle area: 100 △ 4 = 25 (cm2) answer: triangle area is 25 square centimeter

A passenger carrying 30 kg of luggage from Nanjing Lukou International Airport to Tianjin by plane, according to civil aviation regulations, passengers can carry 20 kg of luggage free of charge, overweight part per kilogram according to 1.5% of the ticket price to buy Luggage tickets, now the passenger bought 120 yuan of luggage tickets, then his ticket price is ()
A. 1000 yuan B. 800 yuan C. 600 yuan D. 400 yuan

Suppose his air ticket price is x yuan, then: (30-20) × 1.5% x = 120, the solution is: x = 800

I don't know how to solve the following problems?
（1）5(3a-2b)^2-2(2a+3b)^2-3(2b-3a)^2+4(3b+2a)^2
26a^2+26b^2
（2）[a-(1/2)]^2[a^2+(1/4)]^2[a+(1/2)]^2
a^8-(1/8)a^4+(1/256)
（3）[(-3/4)x^6y^3+(6/5)x^3y^4-(9/10)xy^5]÷(3/5)xy^3
(-5/4)x^5+2x^2y-(3/2)y^2
(4) Given y = ax ^ 5 + BX ^ 3 + cx-2, when x = - 3, y = 4, then when x = 3, find the value of Y

On the horizontal ground, pull 100N wooden box with 60N pulling force. Make the wooden box advance 5m along the direction of pulling force, and the pulling force is less than gravity

Maybe, the pulling force only needs to be greater than the friction force, and the friction force is equal to gravity times the friction coefficient, and the friction coefficient is relatively small

Given the first n terms of sequence {an} and Sn = n ^ 2An, and A1 = 1, guess an by calculating A2, A3, A4=

a1=1
a2=1/3
a3=1/6
a4=1/10
an=1/[1+2+...+(n-1)+n]=1/[(1+n)*n/2]

A car is driving along a straight line at a speed of 8 m / s, and suddenly accelerates at a speed of 1 m / s. find the speed of the car when it accelerates for 18 M
I want to understand

S=(Vt²-Vo²)/2a
So vt & # 178; = 2As + VO & # 178;
Where, a = 1m / s, s = 18m, VO = 8m / s
So vt & # 178; = 2 × 1 × 18 + 8 & # 178; = 36 + 64 = 100
So VT = 10m / s

Xiao Ming and Xiao Gang are doing morning exercises around a 400 meter track. If they are walking from the same place with their back at the same time, they will meet after 2 minutes. If they are walking from the same place, they will meet each other
If two people walk in the same direction at the same place at the same time, then after 20 minutes, they meet. If Xiao Ming is faster than Xiao Gang, what are the speeds of Xiao Ming and Xiao Gang?

Let Xiao Ming and Xiao Gang's speed be x and Y meters per minute respectively, then there is
400/（x+y）=2
400/（x-y)=20
The solution is x = 110m / min; y = 90m / min
That is to say, the speed of Xiaoming and Xiaogang are 110m / min and 90m / min respectively

It is known that the roots of two real numbers of the equation x 2 - (K 2-4k + 3) x - (K-2) = 0 are opposite to each other, the value of K and the root of the equation are obtained

Let two of the original equations be X1 and X2, then X1 + x2 = k2-4k + 3; (2 points) according to the meaning of the question: k2-4k + 3 = 0; K1 = 1, K2 = 3; (4 points) when K1 = 1, the original equation is x2 = - 1, and the original equation has no real root; (5 points) when K2 = 3, the original equation is x2 = 1; X1 = 1, X2 = - 1; (6 points) answer: the value of K is 3, and the two of the equation are 1, - 1. (7 points)