The equation 3x (x-1) = 2 (x-1) is solved by factorization

The equation 3x (x-1) = 2 (x-1) is solved by factorization

3x (x-1) - 2 (x-1) = 0, (x-1) (3x-2) = 0, X-1 = 0 or 3x-2 = 0, so X1 = 1, X2 = 23

If 2A + 3B = 8, 3a-2b = - 1, find the solution of equation (a + 2) x - (3b-1) / 2-ax - (B + 1) / 6 = 2

2a+3b=8
3a-2b=-1
A = 1, B = 2 can be obtained by solving the equations simultaneously
After substituting the values of a and B into the equation, the equation is
3x-5/2-x-1/2=2
The solution is x = 5 / 2

If a + B = 1, a + 3B = - 1, then the solution of the system of equations (a + 2b) x-by = 6, ax + (2a-b) y = 6 is_______ I want 2 yuan per process~

∵ a + B = 1, ① a + 3B = - 1, ② - ① get: 2B = - 2, ② B = - 1, substitute B = - 1 into ① get: a + (- 1) = 1, a = 2, substitute a = 2, B = - 1 into the equation system (a + 2b) x-by = 6, ax + (2a-b) y = 6, get: [2 + 2 × (- 1)] x - (- 1) y = 6 2x + [2 × 2 - (- 1)] y = 6, namely: y = 6 2x + 5Y =

99 times 1 / 100

99 times 1 / 100
=(100-1)×1/100
=100×1/100-1×1/100
=1-1/100
=99/100
In fact, the problem of direct multiplication faster, do not need a simple algorithm
Hope to help you

Given that the sequence {an} satisfies A0 = 1, an = A0 + A1 + A2 +... + a (n-1) (n > = 1), then when n > = 1, an =?

A (n-1) 2An = 1 + SN is Sn = 2an-1 and S1 = A1 = A0 = 1. When n ≥ 2, SN-S (n-1) = 2an-1 - {2A (n-1) - 1} = 2an-2a (n-1) ① SN-S (n-1) = an2, then an / A is obtained

It is known that the polynomial (m-1) x with respect to XY is cubic Y - (n + 4) x, quadratic y is (n minus one) power + 6xy-2
When Mn satisfies what conditions, the multidirectional form is a quartic trinomial form
When m n satisfies what conditions, the polynomial is a cubic trinomial

Write (m-1) x ^ 3Y - (n + 1) x ^ 2Y ^ (n-1) + 6xy-2
(1) If the polynomial is quartic trinomial, then there is no first term or second term. If there is no first term, then M-1 = 0, n-1 = 2, that is, M = 1, n = 3; if there is no second term, then M-1 is not equal to 0, N + 1 = 0, that is, M is not equal to 1, n = - 1
(2) If the polynomial is cubic trinomial, then M-1 = 0, n-1 = 1, that is, M = 1, n = 2

A barrel of oil weighs 12.65 kg. After half use, the barrel weighs 6.85 kg. How many kg of oil is there in the original barrel?

11.6

Let f (x), X belong to R, X is not equal to 0, for any non-zero real number x, y, satisfy f (XY) = f (x) + F (y), find f (1), f (- 1)
Given that f (x) = log base is root 2, the image with index (x + a) passes through the origin, if f (x-3), f (root 2-1), f (x-4) form an arithmetic sequence, find the value of X

(1) Let x = y = 1; f (1) = 2F (1); f (1) = 0. Then let x = y = - 1; f (1) = 2F (- 1); f (- 1) = 0. (2) because f (x) = log base 2, logarithm (x + a) of the image cross the origin, so a = 1; f (x-3) = f (x) = log base 2, logarithm (X-2); f (root 2-1) = 1

How to solve this equation
1.5：2=2.25：x

The product of internal terms is equal to the product of external terms
1.5x=4.5
x=3

A water pipe injects water into a reservoir with a volume of 100 cubic meters at a uniform speed. The time t of water injection and the quantity Q of water injection are shown in the table below
[label: water pipe, reservoir, water injection] soso user 2010-12-14 22:48
(min) ... 2 4 6 8 10 .
Q(m^3) ... 4 8 12 16 20 .
(1) Write the functional relationship between T and Q
(2) When t = 15 minutes and 15 seconds, the water quantity Q in the pool is calculated
(3) What is the change rule of water quantity Q and water injection time t in the pool?

(1)Q=2t
(2) T = 15 minutes 15 seconds = 15.25 (min)
Q=2t=2*15.25=30.5(m^3)
(3) It is shown as a straight line by image, and it will be turned into a horizontal line after being filled with water