A few questions about the calculation of the common factor method, one 4 times the square of (X-Y) minus x times (Y-X) two The solution of (55x + 35) (53x + 26) - (55x + 35) (53x + 27) = 0 is? I don't know much about the common factor

A few questions about the calculation of the common factor method, one 4 times the square of (X-Y) minus x times (Y-X) two The solution of (55x + 35) (53x + 26) - (55x + 35) (53x + 27) = 0 is? I don't know much about the common factor

one
4 times the square of (X-Y) minus x times (Y-X)
=4(x-y)^2-x(y-x)
=4(x-y)^2+x(x-y)
=(x-y)(4x-4y+x)
=(x-y)(5x-4y)
two
(55x+35)(53x+26)-(55x+35)(53x+27)=0
(55x+35)(53x+26-53x-27)=0,
-(55x-35)=0,
11x-7=0,
x=7/11

1. 4m (X-Y) + 6N (Y-X) 2, a (X & sup2; + Y & sup2;) + B (- X & sup2; - Y & sup2;) and an application problem
3. It is known that the area of a large square is the s-corner mark big positive, the area of a small square is the s-corner mark small positive, the area of the ring between the big circle and the small circle is the s-corner mark ring, and the s-corner mark big circle-s-corner mark small circle = 50, so the value of the s-corner mark ring can be obtained
4. Factorization: (1)
1+x+x(1+x)+x(1+x)²+x(1+x)³
（2）
Conjecture: 1 + X + X + X (1 + x) + X (1 + x) & sup2; + X (1 + x) & sup3; +. + X (1 + x) 2009 power

1、4m(x-y)+6n(y-x)
=2(x-y)(2m-3n).
2、a(x²+y²）+b（-x²-y²)
=(x^2+y^2)(a-b).
three
4.（1）1+x+x(1+x)+x(1+x)²+x(1+x)³
=(1+x)^2+x(1+x)²+x(1+x)³
=(1+x)^3+x(1+x)^3
=(1+x)^4.
(2) Conjecture: 1 + X + X (1 + x) + X (1 + x) & sup2; + X (1 + x) & sup3; +. + X (1 + x) ^ 2009
=(1+x)^2010.

How to extract what the common factor is and what formula is there
Use the formula of "a, B" to show me. It's too deep to understand
If: 15A ^ 3 + 10A ^ 2 = 25 (a ^ 3 + A ^ 2) = 25 (a ^ 5) = 25A ^ 5

For example: ab + AC = a (B + C), a on the left is the common factor, and after extracting the common factor, it becomes the one on the right

Help to extract the common factor method to solve the following quadratic equation
① x^3+9+3x^2+3x ② -6x^2+7x+5 ③x^2-(a+b)xy+aby^2 ④2y^2-4y-6
⑤ b^4-2b^2-8 ⑥-13ab^2x^6-39a^3b^2x^5

① x^3+9+3x^2+3x=x²(x+3)+3(x+3)=(x+3)(x²+3) ② -6x^2+7x+5=-(6x²-7x-5)=(3x-5)(x+1)③x^2-(a+b)xy+aby^2 =(x-ay)(x-by)④2y^2-4y-6=2(y²-2y-3)=2(y+1)(y-3)⑤ b^4-2b^2-8=(b²-4)(b²...

In a water pipe with a diameter of 0.8 meters, the water flow rate is 2 meters per second. How many cubic meters of water will flow in one minute?

1 minute = 60 seconds, 3.14 × (0.8 △ 2) 2 × 2 × 60, = 3.14 × 0.16 × 120, = 60.288 (cubic meters); a: this water pipe can flow 60.288 cubic meters of water in 1 minute

Let x tend to zero, the square root of (1 + x ^ 2) minus the square root of (1 + x ^ 3) is infinitesimal equivalent to AX ^ K

When x tends to zero, the square root of (1 + x ^ 2) minus the square root of (1 + x ^ 3)
=1+x/2-(1+x/3)
=x/6
a=1/6
k=1

The quilts have to be packed. Class 61 packed 9 quilts, but the remaining 3 / 5 of the total number. Class 62 continued to pack. Class 62 packed 13 quilts, but the remaining 2 quilts. See the following supplement for the problem
(1) A bag of quilts is a fraction of the total
(2) How many quilts are there in all
The first floor is wrong. It's not a few bags of quilts. It's a few quilts in a bag

According to the meaning of the title,
All 1-3 / 5 = 2 / 5, can play 9 bags
A total of: 9 / 2 / 5 = 45 / 2 packs
Each package is all 1 △ 45 / 2 = 2 / 45
The two classes played a total of 9 + 13 = 22 bags
It's all: 2 / 45 × 2 = 44 / 45
All the remaining 1-44 / 45 = 1 / 45
Two more quilts are known to be left
That is: all 1 / 45 is 2
There are: 2 / 45 = 90 quilts

1 take a small rectangular strip of paper, fold out the bisector of each corner by folding method. Is the quadrilateral formed by the intersection of creases a square? Why?
2. Look up the map of "distribution of major earthquake zones, volcanoes and debris flows in China" in volume 3 of junior high school atlas, and talk about the main areas prone to earthquakes, the areas prone to debris flows, and the characteristics of their topographic distribution (short answer)
Amen! Why no one?

1. It's a square. Have you learned congruence? It's a good proof to use congruence. If you haven't learned it, you can write it like this. It's easy to prove that the quadrangle is a rectangle, and the original image is a rectangle. It's an axisymmetric figure. After such a symmetrical change, it's still an axisymmetric figure, so that one is a square

Two forces F1 = 3N. F2 = 4N to find the resultant force of an object

When the resultant force is greater than 1n and less than 7n, it is the smallest in opposite direction and the largest in the same direction

Solution equation: (110-x) + (130-x) = 120

(110-X)+(130-X)=120
First, remove the brackets and get 110-x + 130-x = 120
Merge the similar items to get 240-2x = 120
We get 2x = 120
We can get x = 60