How to solve the equation x * (x + 2) / 2 = 24? x*(x+2)/2=24 x×（x+2）=24×2 x×（x+2）=48 x²=46 What's the solution?

How to solve the equation x * (x + 2) / 2 = 24? x*(x+2)/2=24 x×（x+2）=24×2 x×（x+2）=48 x²=46 What's the solution?

X * (x + 2) = 48, then the left x should be removed and the solution continued
Become X & sup2; + 2x = 48 and then move the term
X & sup2; + 2x-48 = 0, then cross multiply [this It seems that I was taught on the first and second day of junior high school
(X+8)*(X－6)=0
So, X has two solutions - 8 and 6

On the equation of X: the solution of x-4 / a-6 / ax-3 = 1 is x = 1. For the same a, find the solution of another equation of x-4 / x + a-6 / ax-3 = 1

First, take x = 1 into the equation to get a = 3, and then take a = 3 into the equation to get x = 1

How to solve these equations?
 1.   2.5(x-8)=3x 2.    6.3﹙6x－7﹚＝15x＋12 3.    5.7﹙2x－6﹚＝8  x∶﹙320－240﹚＝5∶16 2∶0.6＝10∶﹙x－2﹚ 0.75∶3＝x∶15 0.7∶x＝12∶24 x∶7.5＝2.1∶1.8 6.5x∶3＝10∶9
The steps of solution should be detailed

(1) 2.5x-20 = 3x 0.5x = - 20 x = - 40 (2) 37.8x-44.1 = 15x + 12 22.8x = 56.1 x = 561 / 228 ≈ 2.46, followed by X: 80 = 5:16

Help me solve some proportion and equation!
1.2.05+7x=8.35 2.（3/5-1/3）x=2/5 3.3x-3/4x=9 4.12x-8+2/3 5.4/3x3/5=19/15 6.x-3/4x=1/8

1.2.05+7x=8.357x=8.35-2.057x=6.3x=0.9 2.（3/5-1/3）x=2/5 4/15x=2/54x=6x=1.53.3x-3/4x=9 12x-3x=369x=36x=44.12x-8=2/312x=26/3x=13/185.4/3x3/5=19/15 6.x-3/4x=1/81/4x=1/8x=1/2

If the function f (x) = [1 / 3 ^ (- 1) - 1] + α is odd, what is the value of real number α

If f (x) is an odd function, f (x) = - f (- x)
Then f (x) = (1 / 3) ^ - X-1 + a = 1-A - (1 / 3) ^ X
a=1-1/2*(3^x+(1/3)^x)
3^x+(1/3)^x>=2
So a & lt; = 0
Is there a D option?

F (x) = (2x-a) / (x ^ 2 + 2) (x belongs to R) in the interval [- 1,1] is a set of increasing function to find the value of real number a

f'(x)=(-2x^2+2ax+4)/(x^2+2)^2>0(x∈(-1,1)),
∴g(x)=-2x^2+2ax+4>0(x∈（-1,1)),
And G (- 1) = 2-2a > = 0,
∴A=[-1,1].

Linear algebra proves that a is an orthogonal matrix of order n, if I a i = 1, it is proved that when n is odd, I e-A I = 0

|E-A | = | e-A | ×| a '| = | a' - AA '| = | a' - e | = | A-E | = | - (e-A) | = (- 1) ^ n | e-A | = - | e-A |, so | e-A | = 0. Where a 'represents the transposition of A

How to distinguish the singular, plural and uncountable nouns in a sentence?
Especially when there is no special determiner, how can they exist and distinguish

It is a very important problem for us to judge whether a noun is countable or uncountable, because it involves adding an article in front of it and adding an appropriate form in a sentence. How to distinguish countable noun from uncountable noun

How to calculate LG 1.8 * 10 ^ - 5 with the test calculator
 

log （1.8*（10^（-5）））
^Yes, press the key XY (the second line, the first on the right)

Can a lot of (or lots of) be followed by uncountable nouns
After a lot

I can learn a lot about Chinese history. I can also learn a lot about Chinese history