Find the value of the following arithmetic expression (1) x + a% 3 * (x + y) / 4, let x = 2.5, a = 7, y = 4.7, and solve the problem with C language program

//#Include "StdAfx. H" / / VC + + 6.0 plus this line
#include "stdio.h"
void main(void){
double x=2.5,y=4.7;
int a=7;
printf("%f\n",x+a%3*(x+y)/4);
}

2+5 7+13 3+6 7+2 4+11 18-6 20-7
2+5
7+13
3+6
7+2
4+11
18-6
20-7

7.20.9.7.9.9.15.12.13

Let a, B, C, D, m, n be int type variables, and a = 5, B = 6, C = 7, d = 8, M = 2, n = 2, then the logical expression (M = a > b) & & (n = C > d) runs
The answer is 2. Please explain it to me. Thank you

I don't know if your topic is complete. If there are only these, the result of the expression (M = a > b) & & (n = C > d) is 0, and the short-circuit evaluation is specific, that is, as long as the result of the previous expression is 0, the later expression will not be operated or judged. (M = a > b) & & (n = C > d) the result of the expression a > b is 0, so

Judgement of the root of complex coefficient equation
It is known that 2x ^ 2 - 2 (1 + I) x + ab - (a-b) I = 0 has a real root. The value range of a, B and the value range of real root can be obtained. Specifically, can we use delta greater than or equal to 0

First of all, delta can not be used to judge the real root of complex coefficient equation. Delta itself may not be a real number. Even if delta is a positive real number, if you write out the root formula, the part outside the root sign delta is not necessarily a real number
Second, there should be real numbers a and B in your question, otherwise it will be troublesome, even real numbers are troublesome
Suppose t is the real root of the equation, then it is sorted out according to the real part and imaginary part
2t^2-2t+ab=0
2t+(a-b)=0
We get t = (B-A) / 2 and take it to the first formula
a^2-ab+b^2+2a-2b=0
This is an ellipse. The range of a and B is the point on the ellipse
As for the range of real roots, we can calculate it by taking two tangent lines of ellipse whose slope is 1

Calculation - 1 / 10 * 11-1 / 11 * 12-1 / 12 * 13. - 1 / 19 * 20
simple and convenient

-1 / 10 * 11 = 1 / 11-1 / 10, and so on, the final result is 1 / 20-1 / 10 = - 1 / 20

It is known that there are two symmetries on the circle C: xsquare + ysquare + 2X-4 = 0 about the line X-Y + M = 0, then M =?

The equation of circle is arranged as follows: (x + 1) ^ 2 + y ^ 2 = 5, the center of circle is (- 1,0) because there are two points on circle C which are symmetrical about the straight line X-Y + M = 0, so the center of circle (- 1,0) is substituted into the linear equation - 1-0 + M = 0, so m = 1

Two fifths minus two fifths multiplied by three eighths is a simple calculation

2/5-2/5×3/8
=2/5×(1-3/8)
=2/5×5/8
=1/4

Y = 3 / 2x & # 178; - 15 / 4x becomes y = a (X-H) + K

y=(3/2)x²－(15/4)x
y=(3/2)[x²－(5/2)x＋(5/4)²]－(3/2)×(5/4)²
y=(3/2)[x－(5/4)]²－(75/32)

What is five five divided by five

A ＜ 0, B ＞ 0 for the absolute value + 1 of formula A, when a takes what value, what is its minimum value?

The title is wrong

Find the value of the following arithmetic expression (1) x + a% 3 * (x + y) / 4, let x = 2.5, a = 7, y = 4.7, and solve the problem with C language program