How to calculate the operation expression containing scientific counting method, for example: 564 * (4.06655e + 100)

How to calculate the operation expression containing scientific counting method, for example: 564 * (4.06655e + 100)

This is equivalent to the associative law of multiplication
564*（4.06655E+100）
=（564*4.06655）E+100）
The specific number can be calculated by using the calculation tool
=2.2935342E+103

If int x = 1, y = 2, what is the result of the expression (y = 0)? + + X / - - Y: + + y?
How to calculate

The result is 1
Because the value of assignment statement depends on the value of assignment object, the value of (y = 0) expression is 0, so the statement after semicolon is executed
After the assignment statement is executed
y=0;
implement
++y;
Add and take again
So the value of the entire expression is 1

A, B and C process parts. A processes 1 / 4 of the total number of parts, and C processes 120 parts. How many parts are there in total

If the total number is x, then 1 / 4x + 1 / 3x + 120 = x, the total number is 288, of which 72 are processed by a, 96 by B, and 120 by C?

Solving equation 42-8 (4-x) = 7x + 6

42—8（4—x)=7x+6
42-32+8x=7x+6
8x-7x=6-10
x=-4

The number of tons of grain in warehouse A is 1.8 times that of warehouse B. If warehouse B carries 560 tons more, then the two warehouses are equal. How much grain does warehouse a store

Let B be x, a be 1.8x, then x + 560 = 1.8x, x = 700, then a be 1.8x = 1.8 * 700 = 1260

Solving mathematical problems by factoring quadratic equation of one variable
（2X-1)²-(2X-1)-6=0

（2X-1)²-(2X-1)-6=0
（2x-1-3)(2x-1+2)=0
(2x-4)(2x+1)=0
x1=2, x2=-1/2

A few math problems, simple operation!
1. (1 and 3 / 4 - 7 / 8 - 7 / 12) × (- 1 and 1 / 7)
2.(-3)^2×＜(-2/3) + (-5/9)＞
3.(5/9 - 5/6 + 1/4) ÷ (-1/36)
4. (- 19 and 18 / 19) × 38
Note: the process should be detailed! There are negative numbers in the four questions```

1. (1 and 3 / 4 - 7 / 8 - 7 / 12) × (- 1 and 1 / 7)
=（7/4-7/8-7/12）*（-8/7）
=7（1/4-1/8-1/12）*（-8/7）
=8*（1/4-1/8-1/12）
=8*1/4-8*1/8-8*1/12
=2-1-2/3
=1/3
2.(-3)^2×＜(-2/3) + (-5/9)＞
=9*[-2/3-5/9]
=9*（-2/3）-9*5/9
=-6-5
=-11
3.(5/9 - 5/6 + 1/4) ÷ (-1/36)
=(5/9 - 5/6 + 1/4) *（-36）
=-36*5/9+36*5/6-36*1/4
=-20+30-9
=1
4. (- 19 and 18 / 19) × 38
=（-20+1/19）*38
=-20*28+38*1/19
=-560+2
=-558

In the equal ratio sequence {an}, A3 = 4 and S3 = 3 are known. The general term formula of this sequence is obtained

Let the first term of the equal ratio sequence be A1, and the common ratio be q ∵ A3 = 4, S3 = 3 ∵ A1 * Q & # 178; = 4 ① A1 (1 + Q + Q & # 178;) = 3 ② ① / ② Q & # 178; / (1 + Q + Q & # 178;) = 4 / 3 ∵ 3Q & # 178; = 4 + 4q + 4q & # 178;; Q & # 178; + 4q + 4 = 0 ∵ Q + 2 & # 178; = 0

4 (12 + 5) - 4 (6-8 + 4), simple operation

60, you can ask if you don't understand

It is known that m and N are the median lines of ladder shaped ABCD, AC, BD and Mn intersect at points F and e respectively, ad = 30cm, BC = 40cm, and the length of EF is calculated

Mn is the median line of ladder shaped ABCD
M is the midpoint of AB, Mn ∥ BC ∥ ad
Ψ MF is the median of △ ABC and me is the median of △ abd
∴MF＝BC/2＝40/2＝20,ME＝AD/2＝30/2＝15
∴EF＝MF-ME＝20-15＝5（cm）