Negative integers with absolute values greater than 1.2 and less than 3.7 have

Negative integers with absolute values greater than 1.2 and less than 3.7 have

A:
one point two

During the "Rhododendron Festival" in Huanggang, 70 employees of a company organized a group to visit and appreciate the scenic spots. The regulations of the scenic spots are as follows: ① tickets are 60 yuan per person, no discount; ② you can take the scenic spot sightseeing bus when you go up the mountain. The sightseeing bus has four seats and eleven seats, each of which is 60 yuan, and eleven seats is 10 yuan per person. The employees of the company are just full of each car, and the total cost is not more than 5000 yuan How many cars are there for each car?

Suppose four seater cars rent x cars and eleven seater cars rent y cars, then: 4x + 11y = 7070 × 60 + 60x + 11y × 10 ≤ 5000, transform 4x + 11y = 70 into 4x = 70-11y, substitute 70 × 60 + 60x + 11y × 10 ≤ 5000, then: 70 × 60 + 15 (70-11y) + 11y × 10 ≤ 5000, the solution is y ≥ 5011, then ∵ x = 70 − 11y4 ≥ 0, ∥ y ≤ 7011, so y = 5, 6. When y = 5, x = 154. When y = 6, x = 1 Rent one four seater and six eleven seater

Xiao Hong wants to make a necklace, so that the number of red beads is six times that of yellow beads?

A total of 42, red 36, yellow 6

How many decimeters is 60 cm

Six decimeters, one decimeter = 10 cm

1) On the straight line, there are two frogs on point a and point B which are 1 meter apart. The frog at point a jumps along the straight line to the symmetrical point A1 about point B, while the frog at point B jumps to the symmetrical point B1 about point A. then the frog at point A1 jumps to the symmetrical point A2 about point B1, and the frog at point B1 jumps to the symmetrical point B2 about point A1, How many meters is the distance from the frog jumping at point a to point B?
2) There is a natural number, the sum of its minimum two divisors is 4, and the sum of its maximum two divisors is 100. What is the natural number?
3) There are three children. One is one year older than the other. The product of their ages is 360. Do you know their ages?
4) There are six boxes containing apples and oranges, including four boxes of apples and two boxes of oranges. The weight of fruits in the box is 6,8,12,16,18 and 21 respectively. It is known that the weight of apples is twice that of oranges. Can you guess which two boxes are oranges?
6) There was a fruit shop that bought 6 boxes of pears and bananas in one day, with the weight of 8,9,16,19,23 and 27 kg respectively. On the first day, only one basket of bananas was sold, and pears were not sold at all. In the remaining 5 boxes, the weight of pears was twice that of bananas. How many grams of bananas were sold? Which baskets of the remaining 5 baskets were pears? Which baskets were bananas?
7) Is the sum of odd and even numbers odd or even? Is the sum of odd and odd numbers technology or even? Is the sum of even and even numbers?
I already have the answer to the first question, which should be 2187 meters, but I don't know what the process is
I'm sorry. I just forgot how to solve the equation
Why divide the fourth and sixth questions by three?

1) 1 + 1 + 2 + 4 + 8 + 16 + 32 + 64 = 128 m 2) the maximum two divisors of 75 are 75 and 25, and the minimum divisors are 1 and 3. 3) x * (x + 1) * (x + 2) = 360 solve the equation, and the result is no integer solution. I guess your problem may not be expressed clearly. It should be that the ages of two children are connected

Math problem, write the formula
1. Pack 15kg candy in small bags, and each bag can hold 3 / 10 kg of candy. At least how many such bags are needed to fill the candy?
2. Xiaoming takes about 9 / 10 meters to walk three steps. He takes about 1000 steps from home to school. How many meters does Xiaoming take from home to school?
3. It costs 80 yuan to buy 2 / 5 kg of Tieguanyin tea. How much does it cost to buy 1 kg of Tieguanyin tea?
4. There is a 4-meter-long water pipe. How many sections can this water pipe be cut according to 1 / 2 of the length of each section?

Three tenths is 0.3KG, 15 divided by 0.3 equals 50, that is, only 50 small bags can fill the candy
9 / 10 △ 3 × 1000 = 0.3 × 10000 = 300m
80 △ 2 / 5 = 80 × 5 △ 2 = 200 yuan
4 △ 1 / 2 = 20 sections

How many cubic meters is 2827500 cubic centimeters equal to

1 cubic meter = 1000000 cubic centimeters
2827500 CC = 2.8275 M3

Travel problem solved by equation in grade one of junior high school

(1) The distance between stations a and B is 240 km. A bus runs 48 km per hour from station a, and a car runs 72 km per hour from station B. one hour after the car runs from station B, the bus runs from station a, and the two cars face each other. A few hours later, the two cars meet?
Let two cars meet in X hours
72x1+(72+48)x=240
120x=168
x=1.4
(2) A tractor must go to pick up the goods. It's 30 kilometers per hour. After 30 minutes of departure, there is something at home to send a car to catch up with the tractor at the speed of 50 km / h. how long does it take for the car to catch up with the tractor?
Let the car catch up with the tractor in X hours
50x=30x+30x1/2
20x=15
x=0.75
1. Party A and Party B are running on the 10km ring road. Party A runs 230m per minute and Party B 170m per minute
(1) How long does it take for two people to meet for the first time if they start from the same place and direction at the same time?
(2) If a runs for 10 minutes and B starts from the same place and direction, how long will it take for them to meet for the first time?
(3) If two people set out in the same direction at the same time, how long will it take for them to meet for the second time?
2. When the plane flies between the two cities, it takes 4 hours to return downwind and 5 hours to return upwind. The speed of the plane in the still wind is 360 km / h. calculate the wind speed and the distance between the two cities
3. A ship arrives at land B 8 hours downstream from land a, and it takes 12 hours to return to land a. the water speed is 3 km per hour, and the distance between a and B is calculated
(1) Let the indirect unknowns solve the equation
Let the ship's speed in still water be x km / h, then the ship's speed in downstream water is and the ship's speed in upstream water is
(2) Let the direct unknown sequence equation be:
If the distance between wharf A and wharf B is x km, the speed of the ship in the downstream is 0__ The speed of the ship in the upstream is__ The corresponding equation is______ The distance between the two terminals is km
4. Soldiers of a certain army walk from the army to the central square to participate in public welfare activities at the speed of 4km per hour. After walking for 1.5h, pony is ordered to go back to the army to get something. He goes back to the army at the speed of 6km per hour to get something and then chases the team at the same speed. As a result, he catches up with the team 2km away from Guangchang to find out the distance between a certain army and the central square
5. The speed of the ship in still water is 16im / h, the current speed is 2km / h, and it goes upstream at 8 a.m. ask how far the ship should go at most to return, so as to ensure that it can return to the departure place before 12 noon?
one
(1) The first encounter is a much better than B run a lap, set after t time
230t-170t=10000
The solution is t = 500 / 3 minutes
(2) A ran for 10 minutes first, and then ran 230 * 10 = 2300 meters, less than 10km, so the first time they met was a better run than B
230*10+230t-170t=10000
The solution is t = 385 / 3 minutes
（3）230t-170t=20000
The solution is t = 1000 / 3 minutes
2. Set the wind speed as V and the distance between the two cities as S
s/（360+v）=4
s/（360-v）=5
The solution is v = 40km / h, s = 1600km
three
（1） x+3 x-3 8*（x+3）=12*（x-3） 15km/h 144
（2） x/8 x/12 x/8-3=x/12+3 144
4. Set the distance as s, then 2km away from the square is S-2
The troops are walking all the time, so the total time of this journey is (S-2) / 4
It takes 1.5 * 4 / 6 = 1 hour for the pony to walk with the brigade Wu for 1.5 hours and then turn back to the original place. Then it takes (S-2) / 6 for the pony to chase from the original place to 2km away from the square, so the total time for the pony is 1.5 + 1 + (S-2) / 6
Big teams and colts should use the same time, so (S-2) / 4 = 1.5 + 1 + (S-2) / 6
The solution is s = 32
5. If you can get back to the starting place at 12 o'clock, it will take 4 hours to go back and forth
x/（16-2）+x/（16+2）=4
The solution is x = 31.5

A simple algorithm of 96 times 25 times 125

96×25×125
=3×4×25×8×125
=3×100×1000
=300000

How to simplify the double radical

A + B √ C radical
Formation a + 2 √ D
Then find X and y
Let x + y = a, xy = D
Then a + 2 √ d = (√ x + √ y) & # 178;
If B is odd
Then (4a + 4B √ C) / 4
So the molecules can be transformed into the front ones