Solve the equation x + 80% x = 12 8x / 1 / 2 = 3 / 5 75% X-1 / 4 = 9

Solve the equation x + 80% x = 12 8x / 1 / 2 = 3 / 5 75% X-1 / 4 = 9

8x / 1 / 2 = 3 / 5
8x÷1/2=3/5
8x=1/2*3/5=3/10
x=3/10*1/8
x=3/80
or
8x÷1/2=3/5
16x=3/5
80x=3
x=3/80
75% X-1 / 4 x = 9
3x/4-x/4=9
x/2=9
x=18

(x + 12) X3 = 48 solution equation

x+12=16
x=4

In the electric field, a point charge of minus 8 power C with charge quantity of - 6 times 10 is moved from point a to point B, and the electric field force does not change
When the work is - 3 times 10 to the power of - 5 C, move the point charge from point B to point C, and the work of electric field force is 4.5 times 10 to the power of - 5 J, find out (1) the potential difference between a and C, and (2) when C is the zero potential point, what is the potential of a

（1）UAB=WAB/q=(-3*10^-5)/(-6*10^-8)=500v
UBC=WBC/q=(4.5*10^-5/(-6*10^-8)=-750v
UAC=UAB+UBC=-250V
(2)φA-φB=UAB
φA=UAB-0=500V
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For the function f (x) = ax + 1 / X-1 (a is a real number, X is not equal to 1), when a = 2, satisfy the condition 2 < X1 < X2, there is always f (x1) - f (x2) < x2
Is this proposition correct?
The derivative solution is required,

First of all, this proposition is correct, and it is proved as follows: F (x1) - f (x2) = (2x1 + 1) / (x1-1) - (2x2 + 1) / (x2-1) through general division, and after simplification, we get: = 3 (x2-x1) / [(x1-1) (x2-1)] because 2 < X1 < X2, so x2-x1 > 0, (x1-1) (x2-1) > 1, so: 3 (x2-x1) / [(x1-1) (x2-1)] < 3 (x2

If the square root of absolute value C 4 of bracket a 1 bracket square B-9 is equal to 0, what is the square root of ABC?

(a + 1) ^ 2 ≥ 0, | B-9 | ≥ 0, radical (c + 4) ≥ 0
(a + 1) ^ 2 + | B-9 | + radical (c + 4) = 0
(a + 1) ^ 2 = 0, | B-9 | = 0, radical (c + 4) = 0
∴a=-1,b=9,c=-4
Ψ radical (ABC) = radical [(- 1) * 9 * (- 4)] = radical 36 = 6

Given that the image of the function f (x) = | SiNx | and y = KX (k greater than 0) have and only have three common points, and the abscissa of the three common points is a, then a =?
If the maximum value of abscissa of the three public electricity is a, then a is equal to a

Because f (x) and y have and only have three common solutions, that is, f (x) and y have only three intersections, the slope of the straight line k = Sina / A and K = (Sina) & nbsp;, # 39; = cosa, so Sina / a = cosa gets a = Sina / cosa = Tana

(| K | - 1) x 2 + (k-1) x + 3 = 0 is a linear equation of one variable about X. find the value of K

According to the meaning of the question, we get | K − 1 = 0k − 1 ≠ 0, and the solution is k = - 1

What is the inverse function of y = 4x - (1 / 2)

The inverse function of Y + 1 / 2 = 4x (y + 1 / 2) / 4 = x is y = (x + 1 / 2) / 4

If the function f (x) = a ^ X / (1 + A ^ x) - A is odd, then the value of real number a is?

Definition of odd function f (x) = - f (- x)
Bring in: A ^ X / (1 + A ^ x) - a = - {a ^ (- x) / [1 + A ^ (- x)] - a} reduction process [a ^ (- x) = 1 / A ^ x]
The simplification is: A ^ X / (1 + A ^ x) + 1 / (1 + A ^ x) = 2xa
That is, 1 = 2xa, a = 1 / 2

Given function f (x) = ax + LNX (a ∈ R)
Given function f (x) = ax + LNX (a ∈ R)
(1) Find the monotone interval of F (x);
(2) Let g (x) = x2-2x + 2, if for any x 1 ∈ (0, + ∞), there exists x 2 ∈ [0,1], such that f (x 1) < g (x 2), the value range of real number a is obtained
The answer is that for any x 1 ∈ (0, + ∞), there exists x 2 ∈ [0,1], such that f (x 1) < g (x 2), equivalent to f (x) max < g (x) max. the range of real number a can be obtained by calculating the corresponding maximum values
Why can we say that instead of F (x) max < g (x) min?

For any x 1 ∈ (0, + ∞), there exists x 2 ∈ [0,1]
In other words, we only need to find a G (x2) greater than f (x) max~
If G (x) max is greater than or equal to G (x), then the original problem ~ is equivalent to f (x) max < g (x) max